Set a value to a pointer in a function

[nutzu2010]

int main()
{
    int *f;
    set(f);
    printf("%d",*f);
    return 0;
}
void set(int *f)
{
    int d=11;
    f=&d;
}

Why it does not work?"It printf" value 0.
d is deleted at the end of function?(I still have lower concerns on dynamic allocation).
I need to create an ordered binary tree.

[grumpy]

You're passing the pointer by value. You can change what it points to, but any change of its value is local to the function.

Even if you fix that, d (inside set()) will not exist either, so printing *f in main() would give undefined behaviour.

Try this

int main()
{
    int *f;
    set(&f);
    printf("%d",*f);
    return 0;
}
void set(int **f)
{
    static int d=11;    /*  One way of ensuring d continues to exist when set() returns */
    *f=&d;
}

[nutzu2010]

So,to create a binary search tree must declare a static node or return the node new created like this?