Linked List Program Error

Hello,
I am writing a simple linked list implementation program... But im facing a problem in printing the contents of list, here is the code..

Code:

#include<stdio.h> 
 
void insert(int value); 
int delete(); 
void showList(); 
 
struct node 
{ 
   int data; 
   struct node *nextNode; 
}; 

//start pointer node 
struct node *start = NULL; 
 
int main() 
{ 
 
   int c=0,value; 
   printf("\nThis Program demonstrates simple Linked List\n"); 
   while(c != 4) 
   { 
      printf("Choices:\n"); 
      printf("Press 1 to insert into Linked List\n"); 
      printf("Press 2 to delete from Linked List\n"); 
      printf("Press 3 to display Linked List\n"); 
      printf("Press  to quit\n"); 
      scanf("%d",&c); 
 
      switch(c) 
      { 
         case 1: 
            printf("\n Enter Value that you want to insert:\n"); 
            scanf("%d",&value); 
            insert(value); 
            break; 
         case 2: 
            printf("\n Deleting first element from List:\n"); 
            printf("\n%d \n", delete()); 
            break; 
         case 3: 
            printf("\n Linked List:\n"); 
                break; 
 
        case 4: 
            printf("\nQuitting.....\n");
            exit(0); 
 
         default: 
            printf("\nNot a valid choice..\n"); 
 
      } 
   } 
 
   return 0; 
} 
 
void insert(int value) 
{ 
     
   struct node *n; 
    n = (struct node *)malloc(sizeof(struct node)); 
   n->data = value; 
    if(start == NULL) 
    { 
        printf("start null\n"); 
        start = n; 
        n->nextNode = NULL; 
     
    } 
    else 
    { 
        n->nextNode = start; 
        start = n; 
    } 
} 
 
int delete() 
{ 
    return 0;     
} 

//this portion is creating problem...  
void showList() 
{ 
    struct node *t; 
    t = start; 
 
    while(t!= NULL) 
    { 
        printf("%d , ",t->data); 
        t = t->nextNode; 
    } 
}

Whenever i choose 3, that is list the contents of list.. it shows blank..
I don't understand where is the fault..

Well the first problem is, you're not even calling showList() anywhere in main.

When you're done inside your loop, calling printf("\n"); would be good as well, to ensure you see output.

Originally Posted by Salem

Well the first problem is, you're not even calling showList() anywhere in main.

When you're done inside your loop, calling printf("\n"); would be good as well, to ensure you see output.

LOL... i forgot tht sorry....
Now it's working.. Thnx!!