Thread: can any one explain me the error.?

Hey all! i m new to dynamic arrays and pointers... can any one explain me the error??

Code:

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>

//-- inputarray defi --
void inputarray(int size, double* array){
     array=(double *)malloc(size*sizeof(double));
     
     int a=0;
     for(; a<size; a++){
           scanf("%lf",(array+a));
                        }     
}
// ** inputarray end **


//-- printarray defi --
void printarray(int size, double* array){
     array=(double *)malloc(size*sizeof(double));
     
     int a=0;
     for(; a<size; a++){
           print("%lf",(array+a));
                        }     
}
// ** printarray end **

//-- main --
int main()
{
    int* arr1, arr2;
    int size1,size2;
    
    printf("Enter the size of aray 1: ");
    scanf("%d",&size1);
    inputarray(*arr1,size1);
    
    printarray(*arr1,size);
    
    
    return 0;
}
//** main end **

Error:

36 C:\Users\Administrator\Desktop\ass 6\2.c [Warning] passing arg 2 of `inputarray' makes pointer from integer without a cast

Are you really sure you want to reallocate memory for array just before printing it? Delete line 19 and see what happens.

lines 11 and 23 would be more explicit (readable) if you used standard array notation... array[a]...

lines 9-10 and 21-22 are screwball ways to initialize a for loop that do little more than reduce the readbility of your code. Use the standard format.... for (a = 0; a < size; a++) ...

lines 36 and line 38 ... lose the asterisks.

In C the order of parameters passed to a function must be correct.

Tim S.

Originally Posted by stahta01

In C the order of parameters passed to a function must be correct.

Tim S.

Nice catch, Tim... I completely missed that.

thnx alll....