confusion with pointers

[baxy]

hi

i have a problem i wish to create an array of pointers to string positions so that when i say string[i] i get the string that starts in the array position i and extends to the end. what i did so far is

:

int test(int n){
	 printf("s \n");
	 char **sarray;
	 int i;
         sarray = (char **)malloc(n * sizeof(char *));
         char *string = "lhfsadgfbfsdaubsdkj";
         printf("s - \n");
         for(i=0;i<n;i++){
            sarray[i]=string[0] + i;
         }
         printf("s\n");
         for(i=0;i<n;i++){
            printf("%s - ",sarray[i]);
         }
}

but the last print gives me a segmentation fault and tried few combinations on how to dereference and print a string but all a get is the random ascii characters

help

thank you

baxy

[Epy]

I don't know what you're trying to do exactly, but this is much easier and straightforward IMO:

#include <stdio.h>
#include <string.h>

int main(void)
{
	char *string = "lhfsadgfbfsdaubsdkj";
	int i, n = strlen(string);
	for (i = 0; i < n; i++)
		puts(string + i);
	return 0;
}

[Epy]

Oh, and here's your problem:

sarray[i]=string[0] + i;

string[0] returns the character at the beginning of the string, you need to use plain string, which is the address of the char array.

try:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(void)
{
     printf("s \n");
     char **sarray;
     int i, n = 10;
         sarray = (char **)malloc(n * sizeof(char *));
         char *string = "lhfsadgfbfsdaubsdkj";
         printf("s - \n");
         for(i=0;i<n;i++){
            sarray[i]=string + i;
         }
         printf("s\n");
         for(i=0;i<n;i++){
            printf("%s - ",sarray[i]);
         }
}