Thread: Using getopt(3c) correctly

Hello all, I'm having trouble with getopt(3c) scanning in characters from command line. Specifically I want to see if two occurrences of the same character are present within the argument.

So for example ./program -abcdd where dd occurs twice.

Currently, I have the scanning as:

Code:

   int x = 0;
   for (;;) 
   {
      int option = getopt (argc, argv, "ab:cd");
      
      if (option == EOF) break;
      switch (option) 
      {
         case 'a': do something;
                   break;
         case 'b': do something;
                   break;
         case 'c': do something;
                   break;
         case 'd': x++;
                   break;
         default : exit;
      }
   }

My logic is that if x occurs twice, then it'll be incremented twice and i can use if ( x==1) or if ( x==2). But this doesn't seem to be working.

I like to use a small int array. As the letter is read, increment the small[letter]. Now you know the distribution, entirely, including doubles.

I don't like incrementing a variabled called 'x', for a duplicate letter of 'd'. You'll need 0-127 for all the low ascii char values, and 0-255 for ALL the ascii char set. Locale sets may be larger, depending on the language they use and their character sets.