long long array problem

I perfer that the result is "0xFFFFFFFFFFFCCFCC"
but in face, the result is "0xFFFCCFCC"?
any bugs in my program?

Code:

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#include <stdio.h>
int    main(void)
{
    int f;
    long long tempdata;
    long long* ptable;




    long long table [16]=
      {
      0xFFFFFFFFFFFCCFCC, //2>
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,
      0xCCCCCCCCCCCCCCCC,    //1
      };






    f=0;
    ptable = table;
    tempdata = *(ptable+(f*256)+(0*16)+0);
    printf("result= %x",tempdata);
    return 0;


}

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The printf specifier "%x" is used to print an int in hex. Since you're using long long at all I assume "int" is smaller than "long long" on your platform, probably 32 bits.

Using "%llx" should work with most compilers, including GCC. MSVC uses something different, from memory it is "%I64x"

1) you need to use printf("result = %llx", tempdata); for 64 bit values

2) if f is ever anything but 0 you are going to cause an integer overflow, which will most likely not be caught because of the lack of runtime checking in C.

Quote:

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Originally Posted by smokeyangel

The printf specifier "%x" is used to print an int in hex. Since you're using long long at all I assume "int" is smaller than "long long" on your platform, probably 32 bits.

Using "%llx" should work with most compilers, including GCC. MSVC uses something different, from memory it is "%I64x"

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worked! thankyou:p