so far the programming i have finds the percentage at which the letters occur however i need help finding the first and second most frequent that occur the code was from a book with a little modification i know i need to use a bubble sort but im having trouble understanding them
heres what i have:
i have 3 variables unused at all because my profesor said to use them to bubble sort for the most frequent letters in the array and to set x[26] = countarray[26] max is the first letter sec is the 2nd most occuring the he also said use for(i=0;i<26;i++) and if(countarray[i]==x) something similar to that,max=x[0] and max[1] and prinf to show the resultsCode:#include <stdio.h> #include <string.h> void getthestring(char string[]); void countcharacters(char string[],int array[],int length); void fixcase(char string[]); void initialize(int array[], int numberelements); main() { char mystring[500]; int countarray[26],x[26],i,j,k,length,max,sec; initialize(countarray,26); getthestring(mystring); length = strlen(mystring); printf("\nyou entered %d characters \n\n",length); fixcase(mystring); countcharacters(mystring,countarray,length); for(i=0;i<26;i=i+1) { printf("%c %5.2f \% ",i+97,((countarray[i]*100.0)/length)); if ((i+1)%5 == 0) printf("\n"); } printf("\n"); getchar(); getchar(); } void getthestring(char string[]) { printf("please enter a sentence,up to 500 characters long\n\n"); gets(string); } void countcharacters(char string[],int array[],int length) { int i,j; for(i=0;i<length;i=i+1) for(j=97;j<123;j=j+1) if(string[i] == j) { array[j-97] = array[j-97] + 1; j=123; } } void fixcase(char string[]) { int i=0; while(string[i] != '\0') { if((string[i] >= 65) && (string[i] <=90)) string[i] = string[i] + 32; i = i + 1; } } void initialize(int array[], int numberelements) { int i; for(i=0;i<numberelements;i = i + 1) array[i] = 0; }
where do i place this stuff though?



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