Can I insert values in an array using "scanf" through the use of pointers?

Hello!
I was wondering if I could insert values in an array using "scanf" through the use of pointers.
I made this code

Code:

---

#include<stdio.h>#define SIZE 4


int main()
{
    int arry[SIZE];
    int *arryPtr = arry;
    int i;


    for( i = 0; i < SIZE; i++ )
    {
        printf( "Enter in Index %d: ", i );
        scanf( "%d", arryPtr );
    }


    printf( "\n\n" );


    for( i = 0; i < SIZE; i++ )
    {
        printf( "%d\n", arryPtr[ i ] );
    }

---

this gives an output like:

Code:

---


Enter in Index : 1
Enter in Index : 2
Enter in Index : 3
Enter in Index : 4

4
-858993460
-858993460
-858993460

Press any key to continue  .  .  .

---

please help me, what should I use?
pointer or array in "scanf"?

Yes. Arrays and index are just syntactic sugar for pointers and offsets (with the offsets themselves being a pointer sometimes).

Computers run (under the hood), on addresses and clock sweeps. LOTS of addresses and clocks sweeps. That's why any language that works low level with the hardware, needs to have pointers. They are hugely powerful, but much more difficult for people to work with than an array with an index.

You don't need to use scanf() however. You can assign a value to any place in the array, directly. That's true with pointers, and also with indices.

You can use scanf(), but you wouldn't normally want to. More work than is needed. Scanf() needs the address of the object it will be changing, so pointer or &array[index], either one.

You can use pointer or array, both will work. The problem in your example is that you're alway writing on the first block of you're array, since arryPtr is pointing to the address of the first block of the array. You can either directly use your array with "&arry[i]", or use the arryPtr with "(array + i)", so you write in the next block at each iteration of your "for" loop.