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Confusion using the DO-WHILE LOOP in C,to assign a control.. Refer to my source code.

This is a discussion on Confusion using the DO-WHILE LOOP in C,to assign a control.. Refer to my source code. within the C Programming forums, part of the General Programming Boards category; I'm writing a small program which asks a user to input 6 numbers. It then displays it on the screen.. ...

  1. #1
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    Nov 2011
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    Confusion using the DO-WHILE LOOP in C,to assign a control.. Refer to my source code.

    I'm writing a small program which asks a user to input 6 numbers.

    It then displays it on the screen..

    (*)Then, it asks the user again if he wants to input any more numbers..

    If the user enters 'y'..he can input another 6 numbers..this goes on and on until he enters 'n' for the question in (*) and the program will end..

    below is the code

    Code:
    int u_num[6];
        char answer;
        int count=0;
    
      do
          
          {   
             printf("Please input any six numbers (from 1 to 40) \n");
        
             for (i=0; i<6; i++)
                 {
                       scanf("%d", &u_num[i]);
                 }
           
             printf(" Your Numbers are:");
                    
             for (i=0; i<6; i++)
                 {
                       printf(" --%d--", u_num[i]);
                 }
                 
                
               
           
                 printf("\n\n Do you want to input any more number? \n\n");
                 scanf("%c", &answer);
           }
               while(answer!='n');
    }
    The problem that is occurring is that I'm getting the message

    "Please insert your 6 numbers" along with
    "Do you want to input any more??"

    [Refer to attachment]

    I just want this "Do you want to input any more??" to be displayed..

    Any help or suggestion???
    Attached Images Attached Images  

  2. #2
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    I don't know if there is a more elegant way, but I find scanf is picking up the return as a character or something,
    so just add another scanf to pick that up, then scanf again so it does not fall through.
    In other words, the 'return' after the sixth number is in the buffer (I think) and that is causing it to fall through.
    There is probably some kind of flush command I have not learned yet.
    I couldn't make your code work at first, there was some things missing.

    Code:
    #include <stdio.h>
    int u_num[6];
    char answer;
    int count=0;
    int i;
    int main (){
    
    
    	do {
    		
    		printf("Please input any six numbers (from 1 to 40) \n");
    	
    		for (i=0; i<6; i++)
    		{
    			scanf("%d", &u_num[i]);
    		}
    	
    		printf(" Your Numbers are:");
    	
    		for (i=0; i<6; i++)
    		{
    			printf(" --%d--", u_num[i]);
    		}
    	
    		printf("\n\n Do you want to input any more number? \n\n");
    		scanf("%c", &answer);
    		scanf("%c", &answer);
    	}
    	while(answer!='n');
    }
    pprav05 likes this.

  3. #3
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    Referring to your first post... line 26 should be...
    Code:
    scanf(" %c",&answer);
    Note the space between the " and the % ... this tells scanf to skip over unseen characters and wait for your entry.

    Note also that n and N are two different things... you should probably check for both, as in line 28...
    Code:
    while ((answer != 'n') && (answer != 'N'));
    pprav05 likes this.

  4. #4
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    Nov 2011
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    I thank you all for your time.. My problem is solved..

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