Annoying Array - Simple Problem ( I hope)

This is a discussion on Annoying Array - Simple Problem ( I hope) within the C Programming forums, part of the General Programming Boards category; Hey guys, I'm working on what should be a fairly simple program. This is a function I'm having trouble with. ...

  1. #1
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    Annoying Array - Simple Problem ( I hope)

    Hey guys, I'm working on what should be a fairly simple program. This is a function I'm having trouble with. It's probably some stupid mistake but if so I can't see it. I want the function to set each variable in an array to a fraction (decimal), but each value after arrays[0] ends up as 0. I'm pretty sure the problem lies within the function after checking the variables while debugging.

    Code:
    double init(double arrays[], int n)
    {
        int counter;
        for (counter = 0; counter <= n; counter++)
        {
        arrays[counter] = 1 / (counter + 1);
        }
        return 0;
    }
    I want the array's values to be set like this:

    a[0] = 1/1, a[1] = 1/2, a[2] = 1/3 ... a[n] = 1/(n+1)

    Any help is greatly appreciated!

    EDIT: I doubt this will help but I started the function in main() using this line: init(arrays, n);
    Last edited by Parrot; 11-05-2011 at 05:04 PM.

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    They will all end up as 0 since integers don't support decimal places, only whole numbers.

    You need to do this with floating point math...
    Code:
    arrays[counter] = 1.0 / (counter + 1);
    You won't actually see 1/4 etc. you will see the decimal equivalent .25.

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    Ohhh, so apparently I needed a 1.0 instead of 1 in my equation.

    I tried it and it seems to work fine. I knew it was something simple like that! Thanks!
    Last edited by Parrot; 11-05-2011 at 07:06 PM.

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    Quote Originally Posted by Parrot View Post
    Ohhh, so apparently I needed a 1.0 instead of 1 in my equation.

    I tried it and it seems to work fine. I knew it was something simple like that! Thanks!
    Yeah, it will do it as an integer unless there's a floating point number in there someplace...

    You're welcome.

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    Quote Originally Posted by Parrot View Post
    Ohhh, so apparently I needed a 1.0 instead of 1 in my equation.
    And if you're short on memory, 1. will work too

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