Thread: Can't get loop to keep running

I'm not sure why, but after I give the input when it prompts me, my program ends.

Here is my program:

Code:

#include<stdio.h>
#include<ctype.h>
#include<string.h>


int main ()
{

int choice;

double app=0;
double tom=0;
double let=0;
double cuc=0;



double appcost=0;
double tomcost=0;
double letcost=0;
double cuccost=0;

int counter;

char cancel[20];

double total=0;

   do
   {
   printf("MAIN MENU\n"// The main menu
   "============\n"
   "Option   Action\n"
   "------   ------------------------------------------\n"
   "   A   -  Purchase apples\n"
   "   C   -  Purchase cucumbers\n"
   "   L   -  Purchase lettuce\n"
   "   T   -  Purchase tomatoes\n"
   "   !   -  Finalize bill of sale\n"
   "   *   -  Cancel this bill and reset 'for' new customer\n"
   "   &   -  Quit program\n\n"
   "Enter the desired option:"
   );
   
   do
   {
   choice = getchar();
   }
   while (isspace(choice) && choice !=EOF);
   
   choice = toupper(choice);
   
      switch (choice) 
		{
		total = app+cuc+let+tom;
			case 'A': //APPLES
			printf("Weight in kg of apples:");
			scanf("%lf\n", &app);
			appcost= app*3.59;
			app=app+app;
			break;
			
			case 'C': //CUCUMBERS
			printf("Number of cucumbers:");
			scanf("%lf\n", &cuc);
			cuccost= cuc*2.29;
			cuc=cuc+cuc;
			break;
			
			case 'L': //LETTUCE
			printf("Number of heads of lettuce:");
			scanf("%lf\n", &let);
			letcost= let*1.49;
			let=let+let;
			break;
			
			case 'T': //TOMATOES
			printf("Weight in kg of tomatoes:");
			scanf("%lf\n", &tom);
			tomcost= tom*1.29;
			tom=tom+tom;
			break;
			
			case '!': //BILL OF SALE
			if (total==0)
			{
			printf("No bill of sale. Nothing has been purchased.\n");
			}
			else
			{
			printf("BILL OF SALE\n"
			"=============\n");
			if (appcost!=0)
			printf("%lf kg apples: $ %lf (TX)\n", app, appcost);	
			if (cuccost!=0)
			printf("%lf cucombers: $ %lf (TX)\n", cuc, cuccost);	
			if (letcost!=0)
			printf("%lf lettuce: $ %lf (TX)\n", let, letcost);	
			if (tomcost!=0)
			printf("%lf tomato: $ %lf (TX)\n", tom, tomcost);
			double sub=appcost+cuccost+letcost+tomcost;
			double hst=sub*0.13;
			double final=sub*1.13;
			printf("\n");
			printf("=============================\n");
			printf("               Subtotal: $  %.2lf  \n", sub);
			printf("                  HST: $  %.2lf   \n", hst);
			printf("                 TOTAL: $  %.2lf   \n\n", final);
			printf("---------------------------------------------------------------\n");
			
			
			}
			break;
			
			case '*': //CANCEL
			printf("Are you sure you want to cancel the current bill (Yes/No)?");
			scanf("%[^\n]", cancel);
		
			   for(counter=0; counter<strlen(cancel); counter++)
			   {
			   cancel[counter] = tolower(cancel[counter]);
			   	 
			/*		if(cancel=='yes')
					 {
					 
					 }
					 if(cancel=='no')
					 {
					 
					 }   */
			   }
			   
				
			}
			if (choice=='&');
			break;
   }
   while (1);
   //while (choice!='&' && choice!=EOF);
    
	

return 0;
}

Thanks for the help in advance!!

This is what I am getting when I run it:


trademark@bravo:~/60-106$ ./a.out
MAIN MENU
============
Option Action
------ ------------------------------------------
A - Purchase apples
C - Purchase cucumbers
L - Purchase lettuce
T - Purchase tomatoes
! - Finalize bill of sale
* - Cancel this bill and reset 'for' new customer
& - Quit program

Enter the desired option:a
Weight in kg of apples:4
a
trademark@bravo:~/60-106$

Code:

        if (choice=='&');
        break;

That ; at the end of the if statement means that there is not body to the if statement, so the break happens no matter what choice is, and your program exits. Also, you may want to remove the \n from your scanf calls, it makes it very difficult to enter weights.