armstrong nos.

[joybanerjee39]

i am trying to write a program which displays the armstrong nos. between 1 and 999.
an armstrong no. is a no. which is equal to the sum of the cubes of its constituent digits. eg. 153=1^3+5^3+3^3

#include <stdio.h>
#include <math.h>
#define  MAX_LIMIT 999
#define  CUBE 3

int main(void)
 {  int units=0,tens=0,no=0,hund=0;
    
    for(no=1;no<=MAX_LIMIT;no++)
    {  
   
      hund=no/100;        //TO FIND THE HUNDREDS DIGIT
      tens=(no%100)/10;    //TO FIND THE TENS DIGIT
      units=(no%100)%10;   //TO FIND THE UNITS DIGIT
      if(no==(pow(hund,CUBE))+(pow(tens,CUBE))+(pow(units,CUBE)))  // ARMSTRONG CONDITION
    
    printf("\n%d is a armstrong no.\n ",no);
  
    }



 
    return 0;

 }

i want your reviews . are there simpler ways to solve this ?
i have another question.
before this concept i tried to get the digits of a no. using another concept.
a no. can be expressed as the sum of the product of the digits and their place values , like 135=(1*100)+(3*10)+(5*1)
so, i declared

 int u,t,h,no;
(h*100)+(t*10)+(u*1)=no;

but, this gives an error lvalue required . why is it so?
please help!!

[Adak]

About the code that had the error:

The equal sign in C doesn't mean equal, it means "is assigned to", and always works from right to left. Your equal sign is on the wrong end of your assignment. Look at the line of code, from right to left, and you'll see the problem.

[joybanerjee39]

About the code that had the error:

The equal sign in C doesn't mean equal, it means "is assigned to", and always works from right to left. Your equal sign is on the wrong end of your assignment. Look at the line of code, from right to left, and you'll see the problem.

thnx for ur reply
but, if i want to implement the logic 135=(1*100)+(3*10)+(5*100)
is there any way that u can suggest?

[manasij7479]

thnx for ur reply
but, if i want to implement the logic 135=(1*100)+(3*10)+(5*100)
is there any way that u can suggest?

Err... the way you want to try to separate the digits isn't possible .
The only other way (other than using a loop) would be to put the number into a small array... and get the place values by indices .

[joybanerjee39]

Err... the way you want to try to separate the digits isn't possible .
The only other way (other than using a loop) would be to put the number into a small array... and get the place values by indices .

i have used ur advice and wrote a program. i have used a 2d array here.but, the problem is that if i give the no. as a whole (ie. not in form of 1st digit, 2nd digit etc.) the no. is stored as a whole (ie. the digits are not accessible separately) but, i want that the user will enter the no. as a whole and the digits can be accessed separately the code that i have written

#include<stdio.h>
int main(void)
{  int x[3][3],i=0;
   printf("enter  no. ");
   scanf("%d",&x[i]);
   printf("\n%d",x[0][0]);
   return 0;
}

now if i enter a no. say 135 then x[0][0] will show 135 not 1
please help!

[manasij7479]

>i have used ur advice and wrote a program. i have used a 2d array here
Why ?.... just get the integer input and use itoa (or the standard compliant alternatives presented here under the heading Portability )

[joybanerjee39]

>i have used ur advice and wrote a program. i have used a 2d array here
Why ?.... just get the integer input and use itoa (or the standard compliant alternatives presented here under the heading Portability )

oh! i didn't know about this function. thnx a lot for ur reference