what is -29368 output in the below code

[learning_grc]

The code below prints -29368 as output at the end if I enter order of matrix 2 and 2 AND Value of matrix as 1,2,3,4

I wonder what that -29368 refers to? is it memory address or anything else?

int matrix[3][3],i,j,n,c;
clrscr ();
printf ("Please enter the order of matrix\n");
scanf ("%d and %d", &n, &c);
printf ("The order of matrix you entered is &d and &d\n", n, c);
printf ("please enter the value of matrix\n");
for (i = 0; i<n; i++)
for (j = 0; j<c; j++)
scanf ("%d", &matrix[i][j]);
printf ("So the matrix is \n");
for (i = 0; i<n; i++)
{
for (j = 0; j < c; j++)
printf ("%d \t", matrix[i][j]);
printf ("\n");
}
printf ("%d\t", matrix[i][j]);
getch ();
return 0;
}

[CommonTater]

First of all... Learn to indent your code according to some consistent theme. You'll be amazed how many errors you can spot just by the way you set up the source code text... Conversely you'll be surprised how many errors are masked by code like you posted above.

Ask yourself what are the values of i and j when you get to line 17...

[jimblumberg]

What value did you enter for n and c? If either of these values are larger than 2 you are writing, reading to values outside of the bounds of your array. Otherwise you are reading a value that was not initialized, so it could be holding anything.

Jim

[learning_grc]

Thanks CommonTater. I will learn slowly indentation also.
@jimblumberg
value of n is 2 and c is 2

And line 17 is matrix[2][2] in original source.

[jimblumberg]

So then at the end of your loops i and j will be equal to 3 and the following line:

[printf ("%d\t", matrix[i][j]);

Edit: Sorry this would be accessing a value that has not been initialized. The i and j values would be 2.

Jim