Hi, I am trying to create a calculator program that only allows the user three attempts, my actul calculator program works fine however i cant figure out where the while loop should go here is my attempt. When i compile it it runs through the calculator but stops after taken the second num!

Code:#include <stdio.h> main() { int num1, num2, sum; int count=0; char operation,dummy; printf("Enter first number: "); /*retrieves first number from user */ scanf("%d", &num1); printf("Enter operation (+ or - or * or /): "); /* retrieves operation from user */ scanf("%c%c%c",&dummy,&operation,&dummy); printf("Enter second number: "); /*retrieves second number from user */ scanf("%d", &num2); while(count<3) if (operation == '+'){ sum = num1 + num2; printf("The sum of %d and %d is %d", num1,num2, sum); } /* if operation is +, will add numbers and show answer */ if(operation == '-'){ sum = num1-num2; printf("Subtracting %d from %d is %d", num2,num1,sum); }/* if operation is -, will subtract and show answer */ if (operation == '*'){ sum = num1 * num2; printf("Multiplying %d by %d is %d", num1, num2, sum); } /* if operation is *, will multiply and show answer */ if (operation == '/'){ sum = num1 / num2; printf("Dividing %d by %d is %d", num1, num2, sum); } /* if operation is /, will divide and show answer */ count=count+1; return 0; }