Thread: Help on simple pointer program

I'm not asking anybody to write the program. All I need is a poke in the right direction or some hints. I'm so lost, I don't know if I'm even in the right ballpark right now. Here is the question:

Write a function that takes a single string as its argument and returns a pointer to the first nonwhite character in the string.

Here is what I have right now:

Code:

#include <stdio.h>

char * point(char s[])
{
    int i;
    char *s_pointer;
    for (i = 0; s[i] != ' ' && s[i] != '\0'; i++)
    {
        s_pointer = &s;
    }
    return s_pointer;
}

int main()
{
    char s[] = "Four score";
    char z = *point(s);
    printf("%s", z);
    return 0;
}

Am I anywhere near the right answer? Please help!

Thank you very much!

When I run the program I'm getting the output as r. It should be F? Any idea what's going on?

Ignoring the check for \0 since that's not a problem, your loop continues while the character isn't a space. F isn't a space, neither is o, u or r. The first space is. So that points out two problems - your loop has the wrong exit criteria and you have an off-by-one error in the character you return.

Also look into the isspace() function instead of comparing against ' '.

The isspace() function is not in the stdio.h library right? Which library is it in?

This is where it's a HUGE help to have help files for your compiler... the library documentation is 1/2 of the toolkit.

It's in ctype.h

Code:

 #include  #include   char * point(char s[]) { 	int i; 	char *s_pointer; 	for (i = 0; s[i] != isspace(*(s_pointer)); i++) 	{ 		s_pointer = &s[i]; 	} 	return s_pointer; }  int main() { 	char s[] = " Four score"; 	int z = *point(s); 	printf("%c\n", (char)z); 	return 0; }

I'm sorry I have no idea why my code is posting sideways

Because the file you are copy/pasting from doesn't have newlines in it...

If you are copying from the forum to re-paste, click the "to plain text" button first.