one problem in C

This is a discussion on one problem in C within the C Programming forums, part of the General Programming Boards category; Determine the largest number that can be formed with all the figures given number. In my opinion you take the ...

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    one problem in C

    Determine the largest number that can be formed with all the figures given number.
    In my opinion you take the number, it becomes a vector of numbers, sort the array and turn back vector of digits in number.
    I think that is a way. OK, but how to do this (it becomes a vector of numbers) ?

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    one problem in C

    completion

    for instance : the number is 62476
    the highest number is 76642

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    Is this related to one problem in C? Keep related posts in the same thread.

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    Read our homework policy.

    And why would you start two threads for this?
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    Yes, that is one way to do it. Look into the % (modulus) operator for separating the digits. Keep them in an array of ints.

    If you want more help than that, try working out a solution by hand (including testing some examples), then code it up. Post your attempt in code tags and ask specific questions.

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    and the hat of wrongness Salem's Avatar
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    Threads merged.
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    While the number is greater than zero, use % modulus 10 to determine the right most digit. Save that to your int array[i]. Divide the number by 10, and increment i.

    To print out your number, you'll need to go backward, digit by digit, from numberArray[i] to numberArray[0]. While(i) is a simple way to start that second while loop.

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    Quote Originally Posted by Adak View Post
    While the number is greater than zero, use % modulus 10 to determine the right most digit. Save that to your int array[i]. Divide the number by 10, and increment i.

    To print out your number, you'll need to go backward, digit by digit, from numberArray[i] to numberArray[0]. While(i) is a simple way to start that second while loop.
    The first half of this applies to the OP's problem, but the second half does not. The problem isn't to reverse the number, it's to rearrange the digits to make the largest possible number.

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    Quote Originally Posted by anduril462 View Post
    The first half of this applies to the OP's problem, but the second half does not. The problem isn't to reverse the number, it's to rearrange the digits to make the largest possible number.
    I'm using the "Divide and Conquer" approach. One step at a time. The fact that the digits are reversed doesn't affect the problem. The digits can now be easily sorted, so their order will change, anyway.

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