2 dimensional array as a function parameter

How does one pass a 2 dimensional array to a function and modify it in the function. I thought I knew this.

For example a function that modifies a one dimensional array is declared as

Code:

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void do_something ( double array[]);

// and I can call it  with
do_something(array); // for some
double array[10];

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Now for an array with 2 rows and 3 columns I have

Code:

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double array[2][3];

//define function that takes this as parameter
do_something(double array[][3]);

// dope. How do I call do_something???

do_something(array);  // gives wrong answer

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Specify both dimensions, and pass the name of the array:

Code:

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void foo( type array[D1][D2] );
...
type array[D1][D2];
foo( array );

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Quzah.

Code:

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double array[2][3];

//define function that takes this as parameter
do_something(double array[][3]);

// dope. How do I call do_something???

do_something(array);  // gives wrong answer

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You need to post an actual example showing how it goes wrong for you, because this is exactly how you would do it.
I suspect there is some other mistake.

The left-most dimension is optional in the array parameter declaration.