Pointer to function with string

**WSUstudent** · 10-10-2011

Code:

This is my first time trying to use a pointer to a function. I wrote this code and from what I understand it should work but it doesn't. Could someone please help me out.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

char (*s1)(char* (*ptr)(void));
char set_text(void);

int main() 
{
char *s2;
s1(set_text); 
printf("%s\n", s2);
return 0;
}


char set_text(void) {
char text[] = "Hello World!";
char *tmp;


tmp = (char*)malloc((strlen(text) + 1) * sizeof(char));


strcpy(tmp, text);
return tmp;
}

**quzah** · 10-10-2011

No. You want:

Code:

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

char *foo( void )
{
    char *c = malloc( 12 );

    if( c )
    {
        strcpy( c, "hello world" );
    }

    return c;
}

int main( void )
{
    char *c;
    char *(*fun)( void ); /* function pointer */
    fun = foo; /* assign function to the pointer */
    c = fun();
    
    if( c )
    {
        printf( "%s\n", c );
        free( c );
    }

    return 0;
}

fun is a pointer to a function that returns a character pointer and takes no arguments.

edit - dupe thread: I am having a hard time making this work. Could someone give me some advice please?

Quzah.

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