I am trying to make a simply calculator that allows the user to continually modify a result using +,-,*, or / , however for some reason my code is only letting me use each operator (+,-,*, or /) one time, before giving me the error message that is supposed to only appear when the user enters a character that is not one of the four basic operators (+,-,*, or /). Actually no matter what I enter the second time it does this. Here is the code. Please help:
Code:// // main.c // calc // // // #include <stdio.h> #include <stdlib.h> #define QUIT 0 #define CONTINUE 1 //---------------math prototype-------------------------- int math (double first, double second, char operator); int main (void) { int equation=CONTINUE; char operation='+'; double result=10.0, modifier; printf("calculator is on.\n"); //printf("%d\n",equation); while (equation==CONTINUE) { //reading user input of operation and a number: scanf("%c%lf", &operation, &modifier); //sending the two values of "result" and "modifier" and the operator character to subfunction called "math" // and putting the result of "result"(+ or - or * or /)"modifier" in to the variable "result": result = math(result, modifier, operation); printf("result=%f\n", result); } return 0; } //----------math----------------------------------------------------- int math (double first, double second, char operator) { if (operator=='+') return (first+second); else if (operator=='-') return (first-second); else if (operator=='*') return (first*second); else if (operator=='/') return (first/second); else printf("%c is an unknown operation. Reenter your last line:\n", operator); return (first); }
Originally Posted by camel-man
