Error in my array code

[abood1190]

the duty of this code is ... it should multiply 1 column array * 1 column array and display the result

i modified the last part of code but still doesn't give correct result
then, last part is wrong !

#include <cstdlib>#include <iostream>
#include<conio.h>


int main()
{
    int m1[20],i,k,m2[20],mult[20],c1,c2,n;


    
        printf("Enter 20 number for First matrix \n");
        printf("\n");
        for(i=0;i<3;i++)
        {
            
                scanf("%d",&m1[i]);
        }
        printf("You have entered the first matrix as follows:\n");
        for(i=0;i<3;i++)
        {
            
                printf("%d\t",m1[i]);
            printf("\n");
        }
        printf("Enter 20 numbers for Second matrix \n");
        printf("\n");
        for(i=0;i<3;i++)
        {
            
                scanf("%d",&m2[i]);
        }
        printf("You have entered the second matrix as follows:\n");
        for(i=0;i<3;i++)
        {
            
                printf("%d\t",m2[i]);
            printf("\n");
        }
        
        printf("Now we multiply both the above matrix \n");
        printf("The result of the multiplication is as follows:\n");
        
                                
                    
                     
              mult[i]=0;  
               for(i;i<6;i++)
               {
                               mult[i]=m1[i]*m2[i];
                printf("%d\n",mult[i]);
                }
            
            printf("\n");
            
         getch();
    
    


    return 0;
}

[CommonTater]

If you only ran your first two arrays up to 3 elements (lines 13 and 27) ... why did you try to print 6 in line 47.
Also you do not intialize i to any start value in that loop so it's going to start wherever you left off in the previous loop, effectively printing elements 3 to 6 of an array where elements 3 to 6 are totally uninitialized.


Moreover you are telling the operator to enter 20 in each... but only accepting 3 (is that just for testing?).

[abood1190]

If you only ran your first two arrays up to 3 elements (lines 13 and 27) ... why did you try to print 6 in line 47.
Also you do not intialize i to any start value in that loop so it's going to start wherever you left off in the previous loop, effectively printing elements 3 to 6 of an array where elements 3 to 6 are totally uninitialized.


Moreover you are telling the operator to enter 20 in each... but only accepting 3 (is that just for testing?).

yeah, i wanted to test
Never mind, i solved it..

[vikasvijayan]

so ur multiplying two 1dimensional arrays.this is the function

for(i=0;i<3;i++)
 {
   mult[i]=0;
   mult[i]=m1[i]*m2[i];
 }
for(i=0;i<3;i++)
 printf("%d",mult[i]);

[CommonTater]

so ur multiplying two 1dimensional arrays.this is the function

for(i=0;i<3;i++)
 {
   mult[i]=0;
   mult[i]=m1[i]*m2[i];
 }
for(i=0;i<3;i++)
 printf("%d",mult[i]);

Close but no cigar...

for(i=0;i<3;i++)
 {
   mult[i]=0;            <--- this line does nothing.
   mult[i]=m1[i]*m2[i];
 }
for(i=0;i<3;i++)       <--- these two loops can easily be combined.
 printf("%d",mult[i]);

Giving...

for(i=0;i<3;i++)
 {
   mult[i]=m1[i]*m2[i];
   printf("%d",mult[i]);
}