Thread: How to copy the content of an array into a pointer

Those macros don't even make sense.

If you want to copy the array to a pointer, there are two main steps

1) Ensure the pointer points at a valid area of memory that can hold a copy of all elements of the array.

2) Copy each element of the array, individually, to the memory pointed to

For example, in some function (using malloc() to allocate memory, and free() to deallocate).

Code:

char    SendCommand[3]={12,1,53};
char   *CopyCommand = malloc(3);          /* assume <stdlib.h> is included */

int i;

for (i = 0; i < 3; ++i)
  CopyCommand[i] = SendCommand[i];

/*   use CopyCommand for something */

free(CopyCommand);   /*   release CopyCommand as we no longer need it */

Try digging out a basic textbook on C. Even the worst such books out there will help you improve.

Originally Posted by firstoption

what i intend to achieve with the above code is to copy the content of my array SendCommand[] into the pointer *ActualData.
I have very little programming experience,i will be very grateful if someone could help me out.
Best regards to all.
firstoption.

Maybe you should solve your problem by trying to gain some more programming knowledge vice just throwing code at the computer. Here are some useful links, I suggest you read through them and then maybe start back with a simple "Hello World" program and work from there:

1. C Made Easy Tutorials
2. Teach Yourself C in 21 Days
3. Steve Summit's Intro to C Notes

That should get you going in the right direction. Additionally, getch() is non standard and should be avoided. You can read How to Keep my Console Open - FAQ for different alternatives.