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Command Line Arqument

This is a discussion on Command Line Arqument within the C Programming forums, part of the General Programming Boards category; I am stuck here , i need some help here , I am trying to read 10 command line arquments ...

  1. #1
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    Command Line Arqument

    I am stuck here , i need some help here , I am trying to read 10 command line arquments ignoring digits and special characters....I have tried

    Code:
    isalpha( argv[x] )
    but i found out that it only takes an int....

    this is what I have done so far ....

    Code:
    
    #include <ctype.h>
    #include <stdio.h>
    #include <stdlib.h>
    
    #define NB_OF_ARGS 
    
    int main(int argc, char **argv) {
        if (argc != NB_OF_ARGS + 1) {
            printf("10 command line arguments please.\n");
            return EXIT_FAILURE;
        }
        
        for (int i = 1; i <= NB_OF_ARGS; ++i)
    
            printf("  %s", argv[i]);
    
        putchar('\n');
        return EXIT_SUCCESS;
    }

  2. #2
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    Quote Originally Posted by code_lover
    but i found out that it only takes an int....
    Therefore, check all the characters of the string using isalpha, say by writing a function with a loop.

    By the way, it looks like you did not actually set NB_OF_ARGS to an integer value, and then since you are using NB_OF_ARGS, your error message should incorporate that instead of hard coding 10.
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    Therefore, check all the characters of the string using isalpha, say by writing a function with a loop.
    What do you mean ..please explain to me ,i didn,t understand .

  4. #4
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    Suppose I provide you with a microscope and ten say, cell samples to examine. The microscope can only be used to examine one cell sample at a time. Will you tell me that the task of examining the ten cell samples is impossible with this microscope, or will you simply examine each cell sample in turn?

    isalpha can only check if a single char is alphabetic. How can you possibly use it to check if an entire string is alphabetic?
    rags_to_riches likes this.
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    Quote Originally Posted by code_lover View Post
    but i found out that it only takes an int....
    this is what I have done so far ....

    Code:
    #define NB_OF_ARGS
    And now many args do you need? (It needs a number!)

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    How Can I read char by char of the argument ....let me say we have two arquments " James John"
    how can i read char by char of j a m e s ......

  7. #7
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    How would you access the first character?
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    Quote Originally Posted by code_lover View Post
    How Can I read char by char of the argument ....let me say we have two arquments " James John"
    how can i read char by char of j a m e s ......
    Run a loop across each string, copying out the desired characters as you go...

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    I can access the first character by argv[1][0]

  10. #10
    C++ Witch laserlight's Avatar
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    Quote Originally Posted by code_lover
    I can access the first character by argv[1][0]
    Right. Therefore, you are not far off from writing a loop to loop over the characters of the string.
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  11. #11
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    What would you do to change to actually counting instead of having a static number there? Go read the loops and arrays tutorials until you can answer that.


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    Quote Originally Posted by quzah View Post
    What would you do to change to actually counting instead of having a static number there? Go read the loops and arrays tutorials until you can answer that.
    Quzah.
    Interestingly enough... he knows how to print all 10 of them with a loop...

  13. #13
    ATH0 quzah's Avatar
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    Quote Originally Posted by CommonTater View Post
    Interestingly enough... he knows how to print all 10 of them with a loop...
    /facepalm


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    If using loop to find each character ....How to i know the size of each arguments
    Code:
    for (int i = 1; i <= NB_OF_ARGS; ++i)
          for(int j = 0 ; ??? ; ++j)

  15. #15
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    If only there were some way to tell when a string ended...


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