Count number of letters...

**~~CommonTater~~** · 09-12-2011

Originally Posted by sponi

Well there's the problem. I don't know how to determine what kind of character it is

Say i use variable char ch;

Do I just use some parameters to determine if it's a letter? ie if(ch>a && ch<z) ?

Also to count the amount of characters inputted of each type?

That's one way to do it...

You will need to do what real programmers do and look in your C Library Documentation for your compiler .... look for functions that help you classify characters as text, as digits, as whitespace etc... isdigit() is one.... what others can you find?

**~~CommonTater~~** · 09-12-2011

Originally Posted by manasij7479

Now look at the 4th / 5th replies.

Shhhhh... don't give away our secrets...

**sponi** · 09-12-2011

Okay well, Im going to sleep soon, i'll try writing the program again and share my results in this thread tomorrow

thanks everyone

**~~CommonTater~~** · 09-12-2011

Originally Posted by sponi

Okay well, Im going to sleep soon, i'll try writing the program again and share my results in this thread tomorrow

thanks everyone

Sounds good... At least you got past the roadblock.

Remember, the first step in writing any program is to analyse the task.
Then you plan what you're going to write (where you are now)
Then you write the code
Finally you test it...

**sponi** · 09-14-2011

Hey guys, I finished the program i was stumped with. After rereading and thinking more about it, it became abundantly clear and following your useful advice CommomTater.

Code:

#include <stdio.h>
#include <stdlib.h>


 char ch,a,b,c;

main()
{
    do{
    printf("\nEnter charater: ");
    ch=getche();
    switch(ch){
        case '0':
        case '1':
        case '2':
        case '3':
        case '4':
        case '5':
        case '6':
        case '7':
        case '8':
        case '9':
        a++;
        break;
        case ';':
        case ':':
        case '.':
        case '>':
        case ',':
        case '<':
        case '/':
        case '?':
        case '"':
        b++;
        break;
        default :
        c++;
        }
    } while (ch!='\r');

    printf("There are %d numbers, %d punctuation, %d letters.",a,b,c);
}

Just wanted to say thanks, and I know this isn't the optimal way to do it but the exercise was supposed to use switch.

**quzah** · 09-14-2011

Since we are implementing sub-optimal switch variations, here's mine:

Code:

switch( isdigit( c ) )
{
    case 0: case EOF: break;
    default: a++; break;
}
switch( ispunct( c ) )
{
    case 0: case EOF: break;
    default: b++; break;
}

Quzah.

**sponi** · 09-14-2011

So how exactly does that work? what is EOF? I've only gotten through the first 3 sections of Teach Yourself C by Herbert Schildt

**AndrewHunter** · 09-14-2011

Originally Posted by sponi

So how exactly does that work? what is EOF? I've only gotten through the first 3 sections of Teach Yourself C by Herbert Schildt

Well, there is your problem, right there.

EOF is a special char reserved for specifying the end of an input stream, it stands for End of File. Quzah was merely pointing out there are standard library functions for doing what you hard coded; the ispunc(), isdigit(),isalpha()...functions that are available in the cctype library.

**quzah** · 09-14-2011

Originally Posted by AndrewHunter

EOF is a special char reserved for specifying the end of an input stream, it stands for End of File.

Close but yet so far. It's not a char, it's a negative integer value that is specifically designed to not be represented as a char. That's why all of the functions that check individual characters take and return integers.

Quzah.

**AndrewHunter** · 09-14-2011

Originally Posted by quzah

Close but yet so far. It's not a char, it's a negative integer value that is specifically designed to not be represented as a char. That's why all of the functions that check individual characters take and return integers.
Quzah.

Haha...yes I did not mean char as in type, I should have just said value. Thank you for specifying.

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