Thread: Malloc converted to a normal array

hi Guys
I am using an algorithm called nelder mead that I have found online. It works as expected however I am trying to port it to an electronics chip. The point is allocating memory when you are talking about a chip with 128KB of space is not a good idea.
The algorithm calls

Code:

#include <malloc.h>

however I understand it is stdlib that holds to functions of malloc???
and it is used here:

Code:

/* allocate the rows of the arrays*/
	v =  (double **) malloc ((n+1) * sizeof(double *));
	f =  (double *) malloc ((n+1) * sizeof(double));
	vr = (double *) malloc (n * sizeof(double));
	ve = (double *) malloc (n * sizeof(double));
	vc = (double *) malloc (n * sizeof(double));
	vm = (double *) malloc (n * sizeof(double));

	/* allocate the columns of the arrays*/
	for (i=0;i<=n;i++) {
		v[i] = (double *) malloc (n * sizeof(double));

Please can someone help me adjust this so that it is no longer allocating specific memory for these arrays.
Thanks

n is 3

This is currently how it is:

Code:

	double **v;     /* holds vertices of simplex */
	double pn,qn;   /* values used to create initial simplex */
	double *f;      /* value of function at each vertex */
	double fr;      /* value of function at reflection point */
	double fe;      /* value of function at expansion point */
	double fc;      /* value of function at contraction point */
	double *vr;     /* reflection - coordinates */
	double *ve;     /* expansion - coordinates */
	double *vc;     /* contraction - coordinates */
	double *vm;     /* centroid - coordinates */
	double min;

	double fsum,favg,s,cent;

	/* dynamically allocate arrays */

	/* allocate the rows of the arrays*/
	v =  (double **) malloc ((n+1) * sizeof(double *));
	f =  (double *) malloc ((n+1) * sizeof(double));
	vr = (double *) malloc (n * sizeof(double));
	ve = (double *) malloc (n * sizeof(double));
	vc = (double *) malloc (n * sizeof(double));
	vm = (double *) malloc (n * sizeof(double));

	/* allocate the columns of the arrays*/
	for (i=0;i<=n;i++) {
		v[i] = (double *) malloc (n * sizeof(double));
	}

What is the ** on the v array?
Cos that is where the problem lies currently?

Oh yeah of course I dont, I am re defining them as arrays. Stupid me.
however what about this malloc call?

Code:

for (i=0;i<=n;i++) {
		v[i] = (double *) malloc (n * sizeof(double));
	}

Whats it doing here, or do i not need this also?

Originally Posted by a.mlw.walker

Oh yeah of course I dont, I am re defining them as arrays. Stupid me.
however what about this malloc call?

Code:

for (i=0;i<=n;i++) {
		v[i] = (double *) malloc (n * sizeof(double));
	}

Whats it doing here, or do i not need this also?

Arrays and Pointers, section 2.14

What do you hope to gain by changing malloc calls to fixed-sized arrays? You'll need the space to hold the data in either case. Do you feel that the overhead of an extra few pointers is what's keeping the data from fitting in memory or is there some other problem?