Thread: why not 1,2,3,4,5 is output when I expected 1,2,3,4,5,6 for below codes

The below code results only 1,2,3,4,5 as output.

I wonder why not "6" as it is written if==6

http://s2.postimage.org/ywhcikrrd/c_example.gif

Actually post your code here using [ code ] tags.

The reason the code doesn't print "6" is that it breaks out of the loop when i==6, and the break statement is before the printf.

Originally Posted by CommonTater

Double Header... Hi Andrew!

Lol....I know, I was waiting for tabstop or somebody to swing in and make it a trifecta.


EDIT: Oh, the link has been fixed. Did anyone else click on it? That is a waste of someone's time....

Originally Posted by tabstop

Not only that, but you've got an animated trace of the flow of program control through the code. So just watch to the end and you'll see what happens!

Now you are asking for way too much.

Originally Posted by tabstop

EDIT: Sorry AH and CT, was slow.

ALSO EDIT: I don't know why I'm initialing everybody tonight either.

I will let it slide this time TP.......

Really nice .gif you have there. Did you bother to look at it?

In short, look at your

Code:

do
{
  if (i==6)
    break;
  printf(//what you are printing);
  i = i + 1
}

The question is, what are you telling the program to do at the

Code:

if (==6)

point?

In C, if you are including 2 or more lines with a if statement you need the open and close brackets surrounding the body of code. Yes C will pick up the first line, but that is it.

What I am seeing is you told your program to break out of the do/while loop when it hits 6. IF you want it to print 6, then you simply need to whisper into the ear of your program and ask nicely. The relationship between man and C is a very special one. C will do everything you tell it to do, no more no less.

A great way I've found to cycle though code that leaves no question to what belongs to what, is like

Code:

#include <stdio.h>

int main()
{
  int i;
  for (i=0; i<6; i++)
  {
    printf("WAIT FOR IT....\n");
  }

  if (i == 6)
  {
    printf("I am a C programming GOD!\n");
  }

  printf("I made you read a silly a message for a total of (%d) times!\n", i);
  return 0;
}

AS you can see the for() and if() both contain 1 line code commands, but there is no question where that line of code belongs.

If I were to change for() to [code]{
int i;
for (i=0; i<6; i++)
printf("WAIT FOR IT....\n");
printf("Hellow World!\n");
[code] The "Hellow World!" will print out only once.