i made an odd loop. when i press 'y' , i want to continue the loop but it does not. any one can give me a solution?
program is given below..
Code:#include<stdio.h> #include<conio.h> void main() {int n; char i='y'; if(i=='y') {printf("Enter a number : "); scanf("%d",&n); printf("\nSquare of %d is %d",n,n*n); printf("\nWould you like to enter another number? (y/n)"); scanf("%c",&i); } getch(); clrscr(); }
- If you want your program to loop then, well, you need to use a loop. "if" isn't a loop, it's just a branch point; there's no return. Your loops are called "for", "while", and "do while".
- Once you get that in, there is the fact that at the end of the block, the value of i must needs be '\n' (unless you were thinking way ahead and typed "4y" at the prompt). To make %c skip enter-key and read a "normal" character, you need to use a space: " %c".
You didn't make a loop - an if() statement is not a loop.
while ()
do while()
Are loops, which test at the start and end of the loop respectively.
You should also have
scanf(" %c",&i);Note the initial space in this format string.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Additionally, void main is wrong. The minimum C program is:
Read about How to define main-FAQCode:int main(void){ return (0); }
Based on you using void main, getch, and conio.h I am going to assume you are also using Turbo C. It is time to get a new compiler. There are plenty of standard compilers out there that are free.
Originally Posted by anduril462
Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.
^ What these guys said. And indent your code, it's much easier to read with proper indentation.
