How to loop a single character?

**spcx** · 08-23-2011

Hello,

I have a little over 3 days of C experience so bear with me!

I understand how to print 1-100:

Code:

for (i = 1; i < 100; i++)
printf("%d\n", i);

And also A-Z:

Code:

for (ch = 'A'; ch <= 'Z'; ch++)
printf("%c\n", ch);

My question is: How can I print a single character for x times?
For example the letter A, 100 times?:

A
A
A
A
A
...

I tried:

Code:

for (ch = 'A'; ch = 'A'; ch++)
printf("%c\n", ch);

But it gives an infinite loop! How can I tell it to only print 100 times or any other ammount?

**AndrewHunter** · 08-23-2011

Umm.....

Code:

for(int i=0;i<100;i++)
     printf("A\n");

Keep reading through your book or whatever tutorials you are using.

**spcx** · 08-23-2011

Originally Posted by AndrewHunter

Umm.....

Code:

for(int i=0;i<100;i++)
     printf("A\n");

Keep reading through your book or whatever tutorials you are using.

Thank you kindly AndrewHunter. I was having a hard time grasping the logic of it but examples like these makes it very easy to follow and understand. Thanks again!

**Darkroman** · 08-23-2011

You don't need to increment ch, you just need to display the char 'A' 100 times.

edit: I'll include some code

Code:

int i;
char ch = 'A';

for (i = 0; i <= 100; i++) {
     printf("%c", ch);
}

the variable i, in this code, is to determine how many times the loop will run.

**laserlight** · 08-23-2011

Darkroman: note that because you used i <= 100, your loop runs 101 times.

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