Thread: what's wrong with this if function

Well, this seems to be a bit strange..
this is the simple palindrome code..

Code:

# include <stdio.h>

int palindrome (int n)
{  
   int rev=0, k;
   
   while (n!=0)
   {
      k = n%10;
      rev = rev * 10 + k;
      n = n/10;     
   }
   
   if (rev == n)
     return n;
   else
     return 0;
}

int main (void)
{
   int n=9009;
   
   printf("%d",palindrome(n));
}

As we know the input N is palindrome.. but its returning 0..
I checked the value of rev after the calculation ... it went fine.
but when I use this condition
if (rev ==n)
something is going wrong inside..
I checked the value of rev & n values after that .. they get turning to 0;

why ?

where's the little bug, that's hiding?

oops .. got the bug.. its very silly.
n is tending to 0 in the whole iteration .