c tricky code

Code:

---

#include<stdio.h>
void main()
{
float a=0.7;
if(a<0.7)
printf("c");
else
printf("a");
}

---

here 'a' should get printed according to me as the condition (0.7<0.7) is false but 'c'
is printed instead can somebody please explain?

That's because floating point values cannot always be represented exactly...

Try this...

Code:

---

#include<stdio.h>
int main( void )  // the correct form of main
{
    float a = 0.7;
   
    prinf("a = %f\n", a);

    if(a < 0.7)
      printf("c");
    else
      printf("a");

      return 0;  // error level returned to OS.
}

---

What did it print for the actual value of a?

And even better you've got two different approximations running around -- 0.7 is a double, while a is a float, hence is rounded to a different number of bits.

Quote:

---

Originally Posted by theju112

Code:

---

#include<stdio.h>
void main()
{
float a=0.7;
if(a<0.7)
printf("c");
else
printf("a");
}

---

here 'a' should get printed according to me as the condition (0.7<0.7) is false but 'c'
is printed instead can somebody please explain?

---

The default data type for floating point numbers in C is double, so if you don't specify when your double gets demoted to a float for comparison you loose accuracy. Try this instead:

Code:

---

int main(void){

        float a = 0.7;

        if(a < 0.7f)
                printf("boo");
        else
                printf("yeah");

        getchar();
        return (0);
}

---

:cool::cool: andrew hunters code is working..yeah!!

Quote:

---

Originally Posted by theju112

:cool::cool: andrew hunters code is working..yeah!!

---

I was as surprised as you were at the news. :rolleyes:


Quzah.

Quote:

---

Originally Posted by quzah

I was as surprised as you were at the news. :rolleyes:
Quzah.

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LOL.....every once in awhile the random keys I press actually produces something.... :biggrin: