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String table and printing english equivalent

This is a discussion on String table and printing english equivalent within the C Programming forums, part of the General Programming Boards category; ok. Trying now. thanks!...

  1. #16
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    ok. Trying now. thanks!

  2. #17
    C++ Witch laserlight's Avatar
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    Quote Originally Posted by AndrewHunter
    Then why don't you make an array, e.g. a string table like your assignment asked for?, e.g.
    Code:
    char * stringTable[10];
    And then fill in your array with the values you want.
    I suggest this instead:
    Code:
    const char *numerals[] = {"one", /* ... */};
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  3. #18
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    Yeah, good point. I thought about that but decided to be lazy with my example.
    Quote Originally Posted by anduril462 View Post
    Now, please, for the love of all things good and holy, think about what you're doing! Don't just run around willy-nilly, coding like a drunk two-year-old....
    Quote Originally Posted by quzah View Post
    ..... Just don't be surprised when I say you aren't using standard C anymore, and as such,are off in your own little universe that I will completely disregard.
    Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.

  4. #19
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    Instead of
    Code:
    char zero = {"zero"};
    or
    char *zero = "zero";
    Think bigger - a two dimension char array, (or an array of pointers to strings), where the word can be associated with it's index (it's row in this case), in the table.

    This is an array of char pointers, which is not the same as a true two dimension char array (like char numbers[][] would be), but it's what you want, here.

    Code:
    char *numbers[] = { "zero", "one", "two"};
    Now numbers[0] will be zero, numbers[1] will be one. The numbers array of pointers, keeps track of where the next string (word) is. So you can just increment the index here, to go to the next word.

    Code:
    for(i=0;i<3;i++)
      printf("%s \n", numbers[i]);
    
    zero
    one
    two
    Note that since these are strings, no mention needs to be made of the column(s). That is all handled for you.

  5. #20
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    Try this on for size... (Solution in 16 lines)
    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    int main (void)
      { int  number = -1;
        char *asword[] = {"zero","one","two","three","four","five","six","seven","eight","nine"};
        
        printf("Enter a number from 0 to 9 : ");
        scanf("%d",&number);
    
        if ((number < 0) || (number > 9))
          { printf("Error: Only numbers 0 - 9 are allowed\n");
            exit(0); }
    
      printf("You entered the number %s\n",asword[number]);
    
      return 0; }

  6. #21
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    Quote Originally Posted by CommonTater View Post
    Try this on for size... (Solution in 16 lines)
    How about this one:
    Code:
    #include <stdio.h>
    #include <string.h>
    #include <ctype.h>
    
    int main(void){
    
    	char input[5] = {0};
    	char *table[]={"zero","one","two","three","four","five","six","seven","eight","nine"};
    	do{
    		printf("\nEnter a number(0-9): ");
    		scanf("%4[^\n]s",input);
    		while(getchar()!= '\n');
    	}while(strlen(input)>1 || !isdigit(input[0]));
    
    	printf("You entered %s",table[input[0]-'0']);
    	
    	return(0);
    }
    Last edited by AndrewHunter; 08-15-2011 at 05:28 PM. Reason: I am a moron. :p
    Quote Originally Posted by anduril462 View Post
    Now, please, for the love of all things good and holy, think about what you're doing! Don't just run around willy-nilly, coding like a drunk two-year-old....
    Quote Originally Posted by quzah View Post
    ..... Just don't be surprised when I say you aren't using standard C anymore, and as such,are off in your own little universe that I will completely disregard.
    Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.

  7. #22
    ATH0 quzah's Avatar
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    Quote Originally Posted by AndrewHunter View Post
    How about this one:
    Code:
    	char *table[]={"one","two","three","four","five","six","seven","eight","nine"};
    	do{
    		printf("\nEnter a number(0-9): ");
    ...
    	printf("You entered %s",table[input[0]-'1']);
    Quote Originally Posted by AndrewHunter View Post
    Did you miss where he stored "zero"
    I missed where you stored it!


    Quzah.
    AndrewHunter likes this.
    Hope is the first step on the road to disappointment.

  8. #23
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    Quote Originally Posted by quzah View Post
    I missed where you stored it!
    Quzah.
    Haha.....good catch quzah. Fixed it, thanks.
    Quote Originally Posted by anduril462 View Post
    Now, please, for the love of all things good and holy, think about what you're doing! Don't just run around willy-nilly, coding like a drunk two-year-old....
    Quote Originally Posted by quzah View Post
    ..... Just don't be surprised when I say you aren't using standard C anymore, and as such,are off in your own little universe that I will completely disregard.
    Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.

  9. #24
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    I did it! A fully-functional code using a string table as suggested. Although not as short, and use of getchars to pause the output. It is working fine and accepted. Thanks to all who commented and gie advice. Especially laserlight, AndrewHunter, Adak, CommonTater and quzah! Final Code.

    Code:
    #include <stdio.h>
    int main()
    {
    char *table[]={"zero","one","two","three","four","five","six","seven","eight","nine"};
    int num;
    do
    {
        printf("Please insert a number between 0-9: ");
        scanf("%d", &num);
        if(num>=0&&num<=9){
           printf("The %d equivalent in english is %s\n", num, table[num]);
           getchar();
           getchar();
           return 0;}
        else
           printf("is out of range!!\n");
           getchar();
    }
        while ((num<0||num>9));
        return 0;
    getchar();
    getchar();
    return 0;
    }

  10. #25
    ATH0 quzah's Avatar
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    Couple of comments:
    Quote Originally Posted by jimmyskabez View Post
    Code:
    #include <stdio.h>
    int main()
    {
    char *table[]={"zero","one","two","three","four","five","six","seven","eight","nine"};
    int num;
    do
    {
        printf("Please insert a number between 0-9: ");
        scanf("%d", &num);
        if(num>=0&&num<=9){
           printf("The %d equivalent in english is %s\n", num, table[num]);
           getchar();
           getchar();
           return 0;}
        else
           printf("is out of range!!\n");
           getchar(); /* this isn't part of the else */
    }
        while ((num<0||num>9));
        return 0; /* your program stops right here */
    getchar(); /* none of this actually happens */
    getchar();
    return 0;
    }
    Also your indentation leaves a lot to be desired. Indent on an opening braces, un-indent on a close.


    Quzah.
    Hope is the first step on the road to disappointment.

  11. #26
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    Why do I suddenly think I should have waited for the thread to hit page 4 instead of half way down page 2?

  12. #27
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    Quote Originally Posted by CommonTater View Post
    Why do I suddenly think I should have waited for the thread to hit page 4 instead of half way down page 2?
    Haha.....oops. You are too logical Tater, at least there was no way my solution could have been reasonably used.
    Quote Originally Posted by anduril462 View Post
    Now, please, for the love of all things good and holy, think about what you're doing! Don't just run around willy-nilly, coding like a drunk two-year-old....
    Quote Originally Posted by quzah View Post
    ..... Just don't be surprised when I say you aren't using standard C anymore, and as such,are off in your own little universe that I will completely disregard.
    Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.

  13. #28
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    Code:
    #include <stdio.h>
    
    int check_digit(int n1);
    
    int main(){
        
        int r,n;
        char *e[10]={"zero","one","two","three","four","five","six","seven","eight","nine"};
        
       
        printf("enter a digit:");
        scanf("%d",&n);
        
        while ((n<0)||(n>9)){
        
        printf("PLEASE ENTER THE DIGIT(0~9):");
        scanf("%d",&n);
        r=check_digit(n);
        
        if(r==0)
          break;
         else
          continue;    
    }
        
        printf("%s",e[n]);
        
        getchar();
        getchar();
        return 0;
    }
    
    int check_digit(int n1){
        if((n1>=0)&&(n1<=9)) return 0;
          else return 1;    
    }

  14. #29
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    Renyu... no matter how many times you try to disguise it it's still going to look like my code...

  15. #30
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    Quote Originally Posted by AndrewHunter View Post
    Haha.....oops. You are too logical Tater, at least there was no way my solution could have been reasonably used.
    Hey there's a plan... I'm gonna follow your lead and start posting code with errors in it!
    (Like I don't already do that sometimes...)

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