Please, can someone give a hand on this

[code_lover]

I have ran the code several times, but its is not outputting anything!!!!!!!!
It suppose to display the multiplication of two numbers whose all the sum of the digits in the column is equal i.e The four columns have an equal sum.

#include <stdio.h>
#include <stdlib.h>

int main(void) {

    int multiplicand, multiplier;
    for ( multiplicand = 100; multiplicand <= 999; multiplicand++ ) 

        for ( multiplier = 10; multiplier <= 99; multiplier++ ) {

            int partial_product1, partial_product2, result;
            
            

            result = multiplicand * multiplier;

            partial_product1 = multiplier  % 10;

            partial_product2 = multiplier / 10;

            if ( partial_product1 < 1000 )

                continue;
            if ( partial_product2 >= 1000 )

                continue;

            if ( result > 9999 )

                continue;

            int s1 ,s2 ,s3 , s4 ,s5 , s_sum;
            

            s1 = multiplicand % 10;

			s2 = multiplier % 10;

            s3 = partial_product1 % 10;
            
            s4 = partial_product2 % 10;

            s5 = result % 10;
            
            s_sum = s1 + s2 + s3 + s4 + s5;
            

            int b1 ,b2 ,b3 ,b4 , b5,b_sum;

            b1 = multiplicand /10 % 10;

            b2 = multiplier /10 % 10;

            b3 = partial_product1 /10 % 10;

            b4 = partial_product2 /10 % 10;
            
            b5 = result / 10 %100;
			 
			b_sum = b1 + b2 + b3 + b4 + b5;
			
			int c1, c2 ,c3,c4,c5,c_sum;
			
			c1 = multiplicand /100 % 10;
			
			c2 = multiplier /100 % 10;

            c3 = partial_product1 /100 % 10;

            c4 = partial_product2 / 100 % 10;
            
            c5 = result / 100% 10;
            
            c_sum = c1 + c2 + c3 + c4 + c5;

            int f1 , f2 , f3 , f4 , f5 ,f_sum;
            
           	f1 = multiplicand / 1000 % 10;
			
			f2 = multiplier / 1000 % 10;

            f3 = partial_product1 / 1000 % 10;

            f4 = partial_product2 / 1000 % 10;
            
            f5 = result  / 1000 % 10;
            
            f_sum = f1 + f2 + f3 + f4 + f5;
            
            if ( s_sum != b_sum && f_sum != s_sum && c_sum != s_sum  )
			 
			continue;
			
			printf ( "%d" ,multiplicand );
			
			printf ( "%d" ,multiplier);
			
		 	printf ( "%d" ,partial_product1);
		 	
			printf ( "%d" ,partial_product2);
			
			printf ( "%d" ,result);
            
          
        }
  
    
    return EXIT_SUCCESS;
}

[quzah]

            partial_product1 = multiplier  % 10;

            partial_product2 = multiplier / 10;

            if ( partial_product1 < 1000 )

                continue;

Why would you ever expect it to get past that if check?


Quzah.

[AndrewHunter]

I count 4 different places where the OP has defined variables, isn't C99 great!?!

@OP- You really should think about how you are structuring your program flow, you are verging on excessive with your use of continue.

[code_lover]

i have changed that to

if ( partial_product1 > 9999 )

but it is output a different thing.
any idea !!???


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[AndrewHunter]

but it is output a different thing.
any idea !!???


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No, I have no idea what you are saying. Please explain yourself more clearly and use examples of what is going wrong and what you expect to have happen.

[ArunS]

i have changed that to

if ( partial_product1 > 9999 )

but it is output a different thing.
any idea !!???


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What exactly you want to implement?
Give some comments on your previous code, then only we can understand what u did and what u supposed to???????