Hi I have the following struct as below
I have a pointer declaredCode:typedef struct{ union{ typedef struct{ int b; }c; typedef struct{ int e; }f; }u; }a;
and a char buffer which I want to cast the struct c ontoCode:a* pter=(a*) malloc(sizeof(a));
I am not sure how to go about doing this
Or how do I access the struct c from the union?Code:pter=(a*)(c*)buffer;
You don't need to typecast the return from malloc. If you do, you either forgot a header or you are using C++ not C. On to your question: The same way you access any nested structure's members:One has to wonder why you wrapped your union in a struct that contains nothing else.Code:a *ptr = malloc( sizeof *ptr ); ptr->u.c.b = 0xDEADBEEF;
Quzah.
Hope is the first step on the road to disappointment.
Aren't the two structs in the union basically the same?
Ug. He's adding typedefs inside his union. So he didn't actually create instances of f and c, he just made types without actual variables. I discovered this when I was going to make a joke about "No, they're not the same, one is named f and one is named c!" My compiler weeps. It didn't error or warn, it just started crying.
Quzah.
Hope is the first step on the road to disappointment.
That would be a.c.b ...Originally Posted by Edelweiss
What exactly are you trying to accomplish... not in code, in words...
If you simply want to overlay a char array on an int you can do it like this...
This will let you do stuff like this...Code:union t_ctoi { unsigned char chs[sizeof(int)]; int num; } ctoi;
Code:ctoi.num = 4242424242; printf("%c" ctoi.chs[2];
Ops...sorry for giving a lousy example.
Wanted to cast a struct from a union onto a char buffer and the structs in that union are supposed to have different variables.
But I figured it out already. I initialized struct a and and access the struct which i wanted and cast it on the char buffer.
