Thread: Trouble with command-line arguments in C code (Linux)

Hi,

The following is an excerpt from a simple unit converter program I am writing. It compiles with no errors, but the code within the if statement under // Convert units, is not run. I have checked that argv[ARG_CONV_FROM] and argv[ARG_CONV_TO] actually do contain the correct data. I assume there must be some incompatibillity issue between the data contained in argv and the "celcius" and "fahrenheit" strings, but I cannot find the error. Please help

Code:

...

int main(int argc, char *argv[]) {
	// Variables and constants;
	double result = 0;
	const int REQUIRED_ARGS = 4;
	const int ARG_VALUE = 1;
	const int ARG_CONV_FROM = 2;
	const int ARG_CONV_TO = 3;
	
	// Check user input
	if (argc != REQUIRED_ARGS) {
		show_usage();
		exit(1);
	}
	
	// Convert units
	if ((argv[ARG_CONV_FROM] == "celcius") && (argv[ARG_CONV_TO] == "fahrenheit")) {
		result = atoi(argv[ARG_VALUE]) * (9 / 5) + 32;
	}

	printf("Result = %f\n", result);
	return 0;
}

...

Using GCC 4.6.0 on Linux Fedora 15

Thanks Much appreciated