No result out for this CP

This is a discussion on No result out for this CP within the C Programming forums, part of the General Programming Boards category; No any result out for tis CP. Any one can help? TQ Code: #include <stdio.h> main() { int i,split,n_split; float ...

  1. #1
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    No result out for this CP

    No any result out for tis CP. Any one can help? TQ

    Code:
    #include <stdio.h>
    
    main()
    {
        int i,split,n_split;
        float km,n_km;
    
    
        printf("Miles\tKilometers\tMiles\tKilometers\n");
    
        for(i=1;i<=split;i++)
        {
            km=i*1.61;
            split=(1+20)/2;
            n_split=split+i;
            n_km=n_split*1.61;
            printf("%d\t%.2f\t\t%d\t%.2f\n",i,km,n_split,n_km);
    
        }
    
        return 0;
    }

  2. #2
    Registered User manasij7479's Avatar
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    Quote Originally Posted by leevenchoon View Post
    No any result out for tis CP. Any one can help? TQ

    Code:
    #include <stdio.h>
    
    main()
    {
        int i,split,n_split;
        float km,n_km;
    
    
        printf("Miles\tKilometers\tMiles\tKilometers\n");
    
        for(i=1;i<=split;i++)
        {
            km=i*1.61;
            split=(1+20)/2;
            n_split=split+i;
            n_km=n_split*1.61;
            printf("%d\t%.2f\t\t%d\t%.2f\n",i,km,n_split,n_km);
    
        }
    
        return 0;
    }
    What did you expect it to do ?
    Shouldn't you give an initial value to split ?
    Manasij Mukherjee | gcc-4.8.2 @Arch Linux
    Slow and Steady wins the race... if and only if :
    1.None of the other participants are fast and steady.
    2.The fast and unsteady suddenly falls asleep while running !



  3. #3
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    You have not initialised the variable named split before the loop. That means your code exhibits undefined behaviour due to accessing the value of an uninitalised variable, which means ANYTHING is allowed to happen.

    In practice, you are probably getting lucky, and split probably contains a value less than 1, so the loop body is never executed. However, with undefined behaviour, more gruesome possibilities are feasible, such as the program being terminated with segmentation violation or it simply reformatting your hard drive.

    The solution is to initialise split to something that makes sense before the loop, not within the loop body.
    Right 98% of the time, and don't care about the other 3%.

  4. #4
    C++まいる!Cをこわせ! Elysia's Avatar
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    It would be helpful if you posted C in the C section, not the C++ section.
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

  5. #5
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    Quote Originally Posted by Elysia View Post
    It would be helpful if you posted C in the C section, not the C++ section.
    I think your expectations are set just a little too high
    Quote Originally Posted by anduril462 View Post
    Now, please, for the love of all things good and holy, think about what you're doing! Don't just run around willy-nilly, coding like a drunk two-year-old....
    Quote Originally Posted by quzah View Post
    ..... Just don't be surprised when I say you aren't using standard C anymore, and as such,are off in your own little universe that I will completely disregard.
    Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.

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    Quote Originally Posted by AndrewHunter View Post
    I think your expectations are set just a little too high
    Elysia has given fair guidance, and his expectations are reasonable, so I think you set the bar a little too low.
    Right 98% of the time, and don't care about the other 3%.

  7. #7
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    Quote Originally Posted by grumpy View Post
    Elysia has given fair guidance, and his expectations are reasonable, so I think you set the bar a little too low.
    I was not suggesting anything to the contrary. It was just meant as a joke; no offense intended.
    Quote Originally Posted by anduril462 View Post
    Now, please, for the love of all things good and holy, think about what you're doing! Don't just run around willy-nilly, coding like a drunk two-year-old....
    Quote Originally Posted by quzah View Post
    ..... Just don't be surprised when I say you aren't using standard C anymore, and as such,are off in your own little universe that I will completely disregard.
    Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.

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    Any idea how 2 fix it?

  9. #9
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    You were told how to fix it. Where do you define split(in red)? Is it before or after you use it(in green)?
    Quote Originally Posted by leevenchoon View Post
    Code:
    #include <stdio.h>
    
    main()
    {
        int i,split,n_split;
        float km,n_km;
    
    
        printf("Miles\tKilometers\tMiles\tKilometers\n");
    
        for(i=1;i<=split;i++)
        {
            km=i*1.61;
            split=(1+20)/2;
            n_split=split+i;
            n_km=n_split*1.61;
            printf("%d\t%.2f\t\t%d\t%.2f\n",i,km,n_split,n_km);
    
        }
    
        return 0;
    }
    Quote Originally Posted by anduril462 View Post
    Now, please, for the love of all things good and holy, think about what you're doing! Don't just run around willy-nilly, coding like a drunk two-year-old....
    Quote Originally Posted by quzah View Post
    ..... Just don't be surprised when I say you aren't using standard C anymore, and as such,are off in your own little universe that I will completely disregard.
    Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.

  10. #10
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    i test at dev C++ have problems. but my friends test at Code Blocks no problems.

  11. #11
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    Quote Originally Posted by grumpy View Post
    You have not initialised the variable named split before the loop. That means your code exhibits undefined behaviour due to accessing the value of an uninitalised variable, which means ANYTHING is allowed to happen.
    Hence undefined. Move your variable definition to before your for loop.
    Code:
    split=(1+20)/2;
    for(i=1;i<=split;i++)
        {
            km=i*1.61;
            n_split=split+i;
            n_km=n_split*1.61;
            printf("%d\t%.2f\t\t%d\t%.2f\n",i,km,n_split,n_km);
    
        }
    Quote Originally Posted by anduril462 View Post
    Now, please, for the love of all things good and holy, think about what you're doing! Don't just run around willy-nilly, coding like a drunk two-year-old....
    Quote Originally Posted by quzah View Post
    ..... Just don't be surprised when I say you aren't using standard C anymore, and as such,are off in your own little universe that I will completely disregard.
    Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.

  12. #12
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    Give some initial value greater than i, that is greater than 1 to split so that loop can be initialized. Change x to any value>i.

    Code:
    int i,split=x,n_split;
        float km,n_km;
        clrscr();
    
    
        printf("Miles\tKilometers\tMiles\tKilometers\n");
    
        for(i=1;i<=split;i++)
        {
            km=i*1.61;
            split=(1+20)/2;
            n_split=split+i;
            n_km=n_split*1.61;
            printf("%d\t%.2f\t\t%d\t%.2f\n",i,km,n_split,n_km);
    
        }

  13. #13
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    Quote Originally Posted by PrashantDhamija View Post
    Give some initial value greater than i, that is greater than 1 to split so that loop can be initialized. Change x to any value>i.
    There is no reason to do this. Split does not get calculated in the loop, it is a constant. Simply moving it to before the for loop is all that is required.
    Quote Originally Posted by anduril462 View Post
    Now, please, for the love of all things good and holy, think about what you're doing! Don't just run around willy-nilly, coding like a drunk two-year-old....
    Quote Originally Posted by quzah View Post
    ..... Just don't be surprised when I say you aren't using standard C anymore, and as such,are off in your own little universe that I will completely disregard.
    Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.

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