How to point an address of one struct to another struct variable

I want the address of l_temp passed to l, is the syntax i provided right?!

Code:

struct local_stack_def{
	_cc_status cc;
	char command_E[30];
	char DataEntry[200];
	char  user_id_E[200];
	char curr_vol_subvol[ZSYS_VAL_LEN_FILENAME];
	char program_name_DB[ZSYS_VAL_LEN_FILENAME];
	short ret_attr_count;
	short ret_values_maxlen;
	short user_maxlen;
	char curr_vol_subvol_t;
	int x, j, val1, val2, val3;
	short user_curlen, piece_length, fullname_length;
	short fpointer, error, resultFD,resultFM, resultUGI,resultGIL, resultFR,ret_val_length;
	union {
		   long  id_32;
		   short id_16[2];
		  } user_id;
	struct {
		 short paid;
		 short prgm_len;
		 char  prgm_name_E[ZSYS_VAL_LEN_FILENAME];
		   } ret_vals;		   
	 struct {
	   char val[20];
	} command_DB[2];
	 struct {
	   char val4[50];
	} user_id_DB[2];
	struct {
	   short val5[5];
	} attr_list[2];
};

struct local_stack_def l_temp;
struct local_stack_def l = *l_temp;

No. Recall how to declare a pointer and what is the address-of operator.

Originally Posted by KMAN999

I want the address of l_temp passed to l, is the syntax i provided right?!

The "passing" of data in programming-speak generally refers to function parameters. Eg, you pass an argument to a function. I think you mean you want the address of l_temp assigned to l. Assignment is setting the value of a variable. So, eg, you might pass data to a function which the function then assigns to a variable.

To assign the address of l_temp, you need a pointer and the "address of" operator (&):

Code:

struct local_stack_def *l = &l_temp;

Hmm....Can I dereference an object?

Originally Posted by MK27

The "passing" of data in programming-speak generally refers to function parameters. Eg, you pass an argument to a function. I think you mean you want the address of l_temp assigned to l. Assignment is setting the value of a variable. So, eg, you might pass data to a function which the function then assigns to a variable.

To assign the address of l_temp, you need a pointer and the "address of" operator (&):

Code:

struct local_stack_def *l = &l_temp;

Thank you!

Always remember '*' will hold the address of an identifier which can be retrieved by &. Something like this

Code:

int *p;   ===> So p is prefixed by *, which mean it can hold an address. But currently it dosn’t hold any address
int a = 10;  ===> 'a' is just an variable of type int.
p = &a ;  ====> So 'a' is prefixed by '&' which means that your receives the address of 'a' and assigning it to p. So that P is not pointing to where 'a' resides.

ssharish