Thread: Display own name

Hello everyone,
I need to do a program that displays its own name.
So that, when I execute the program, let's say example.exe, "example" will be
printed on the screen.
Any ideas?

Thanks in advance

Originally Posted by grumpy

quzah's use of the word "may" reflects the fact that the content of argv[0] -if any - is implementation defined. argv[0] may be a NULL pointer. If it is not a NULL pointer, it may yield an empty string (""), the name of an executable, a full path to the executable, or some other representation.

If argv[0] does not contain the name of the executable then the method to obtain it (eg API functions to call) is system dependent.

Thanks for the fast reply. As a matter of fact argv[0] contains the filename, but it is giving me the whole path like c:desktop \bla bla\mypro.exe

I only need the filename. Is there a way to parse only the filename from that ?

Many thanks

Originally Posted by laserlight

Yes, e.g., search for the last '\' and take the part after that.

I am so sorry but I am a newbie, could you please show me how to do this on C?

Take a look at this tutorial It should help you implement what Laser said.

Thank you very much!