I'm having severe difficulty creating a multiplication table. I need to create a multiplication table that looks like this by multiplying i*j

1*1= 1 1* 2=2 1* 3=3 1* 4=4 1* 5=5

2*1= 2 2* 2=4 2* 3=6 2* 4=8 2* 5=10

3*1= 3 3* 2=6 3* 3=9 3 * 4=12 3* 5=15

4*1= 4 4* 2=8 4*3=12 4* 4=16 4* 5=20

5 1= 5 5* 2=10 5*3=15 5* 4=20 5* 5=25

This is what I have. I can get a table of i*j I just need to figure out how to put a for statement that could increment itself 5 times for j and start over and then have i increment by 1.

Thanks everyone.Code:#include <stdio.h> #include "conio.h" const int num_rows = 5; const int num_columns = 5; int main(void) { int row, column, i, j; printf("i*j\t", '*'); for (i= 1; i<=5; i++) if (i <= 5) break; printf( "%d", i); for (column = 1; column <num_columns; column++) printf("i*j\t", column); putchar('\n'); for (i= 1; i<=5; i++) if (i <= 5) break;,md for (row =1; row <num_rows; row++) { printf("i*j\t", row); for(column =1; column < num_columns; column++) { printf("i*j\t", row *column); } printf("\n"); } _getch(); return 0; }