Thread: how to pass in a pointer to a pointer

  1. #1
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    how to pass in a pointer to a pointer

    Code:
    // sock_create signature ... 
    int sock_create(int family, int type, int protocol, struct socket **res);
    
    struct bam {
        union am *lay;
    };
    
    struct cam {
        struct socket *skt; 
    };
    How do I pass in the skt member of 'struct cam' to function sock_create() which has arg that requires a pointer to a pointer?

    Code:
    	struct bam *bm;
    	struct cam *cm;
    
    	// ...
    
            cm = (struct cam *)bm->lay;
            
    	// cm->skt wrong here, but not sure how to pass in.
            ret = sock_create(AF_INET, SOCK_STREAM, IPPROTO_TCP, cm->skt);

  2. #2
    C++ Witch laserlight's Avatar
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    Take the address of the pointer
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  3. #3
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    Quote Originally Posted by laserlight View Post
    Take the address of the pointer
    I understand that's what I need to do, but confused on the syntax ... &(cm->skt)

  4. #4
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    Yep, though you don't need the parentheses.
    It is too clear and so it is hard to see.
    A dunce once searched for fire with a lighted lantern.
    Had he known what fire was,
    He could have cooked his rice much sooner.

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