pointers and strings

Code:

---

#include <stdio.h>
#include <string.h>

#define MAX 4

int main(){

  char str[2][MAX] ={"mom", "dog"};
  char *pch;
  char *pch1;

  *pch = str[0][1];

  *pch1 = pch+MAX;

  printf("%c, %p", pch1, pch1);

  return 0;

}

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Hi, I want to be able to compare if the middle letters are the same. This is just a snippet. I wanna see if I can add the MAX (4) including the '/O' character to the pointer to get into the next string.

You know what I mean?

:P

That is correct -- adding the size of the second dimension to a pointer will move you "down" a column in your array.

I don't understand - the value of the middle letters won't affect where the next string is located. The length of the string will.

edit: Nevermind, I see what you are asking. ;)

Several issues. You should not assign the letter 'o' (or any value) to what pch points to when that pointer was not initialized. Same goes for pch1.
I think what you meant was:

Code:

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pch = &str[0][1];
pch1 = pch + MAX;
printf("%c, %p", *pch1, pch1);

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Note carefully the absense of '*' in the pointer assignments, the use of '&', and the inclusion of '*' when you wish to display the character.

Good catch -- you want to assign the value of pch, not the value of *pch.

I also wanted to add:
Because your array is 4 wide, yes you can add 4 to get to the same place in the next row. It has nothing to do with terminating '\0' in the strings.

Quote:

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Originally Posted by nonoob

It has nothing to do with terminating '\0' in the strings.

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I think what he was trying to say was that all the text was 3 chars long, so 3 + the NULL would be 4.

Ah thank you. I kept ending up getting S

And I was wondering why I was only adding 4 to the ASCII numbers.

Thank you again.

I get confused when to put the *.

Quote:

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Originally Posted by mike65535

I think what he was trying to say was that all the text was 3 chars long, so 3 + the NULL would be 4.

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Right, but that's not why it works -- it works because the second dimension of the array is 4, regardless of what's actually in the array itself.