Thread: quadratic equation solving

i use codeblocks for compiling.
The following is the code that i have written for solving quadratic equation.

Code:

#include<math.h>


main()
{

    float a,b,c,discriminant,root1,root2;
    printf("input values of a,b, and c\n");
    scanf("%f %f %f",&a,&b,&c);
    discriminant = (b*b - 4*a*c);
    if (discriminant<0)
       printf("\n\nROOTS ARE IMAGINARY\n");
    else
     {
         root1=(-b+sqrt(discriminant))*1/(2.0*a);
         root2=(-b-sqrt(discriminant))*1/(2.0*a);
         printf("\n\nRoot1=%f\n\nRoot2=%f\n,root1,root2");

     }

}

but when i enter the numbers 2,4,-16
it shows
root1=0.000000
root2=0.000000

i dont know what is wrong can anybody please help

Code:

printf("\n\nRoot1=%f\n\nRoot2=%f\n,root1,root2");

Do you see anything wrong with this statement? Pay attention to the warnings your compiler emits. Also, include <stdio.h>

Include stdio.h which include prototypes of printf,scanf,...
main function signature should be int main(void) and return 0 at the end.

Code:

int main(void)
{
   ....
 return 0;    // success
}

Code:

         printf("\n\nRoot1=%f\n\nRoot2=%f\n,root1,root2");
         printf( format_string,  ....);
  eg. printf("int %d\n", 3);
         printf("root = %f\n",root);