Just for the sake of wanting my own programs to not scroll off endlessly (Gets annoying after a time), I am wondering if C has any way to pause the program after it scrolls through a determined (or built-in) number of lines. Either works fine, but i'd just like my stuff to stop scrolling 4000 lines before I get a chance to actually see it.
Thanks, cheers.
Not built into the basic printf type funcitons. You can just pipe your output through a pager like more or less, e.g. "my_program | less". Otherwise, you would need your own print functions that have a buffer with the number of lines you want, and use those instead of printf et al. When that fills up, print all the lines to screen and clear the buffer. Note you will have to manually count newlines in the formatted text, so you know how many actual lines you have, instead of how many calls to my_printf.
As an alternative, "lazy" alternative you could throw in an empty getchar(). Which will just wait for you to hit enter before continue. But if you have more/less available, it's probably the easiest way of doing this as you don't even need to modify your code.
#include<unistd.h>
usleep(amount of time to wait);
Place usleep(); after any part you want to pause.
Example:
Let me know if this helps...Code:#include<stdio.h> #include<unistd.h> #define NUM_STARS 5 void diamond( int len ) { int i, sp; //print stars diagonaly left to right for (i = 0; i < len; ++i) { printf(" "); for(sp = 0; sp < i; ++sp) { printf(" "); } printf("*\n"); usleep(60000); } //print stars diagonaly right to left for (i = len - 2; i >= 0; --i) { printf(" "); for(sp = 0; sp < i; ++sp) { printf(" "); } printf("*\n"); usleep(60000); } } int main(void) { int t; int x; srand( time(0) ); for (t = 1; t >= 0; ++t) { x = rand()%21 + 7; diamond (x); } return 0; }
Last edited by DuckCowMooQuack; 04-18-2011 at 09:22 PM.
