Odd printf behavior?

I just compiled the program below in Cygwin and on codepad

int main()
{
int k=1;
printf("%d, %d, %d\n", k, k++, k++);
}

In both cases the output was

3, 2, 1

Shouldn't it be the other way around?

Any thoughts would be welcome.
:)

You're engaging in undefined behavior due to sequence points. If you're being taught this, your instructor is an idiot.

It is undefined what order the parameters of a function are evaluated in. In practice, many compilers will do them in the reverse order because that's how they get pushed on the stack, but don't depend on that.

Another dupe thread -> http://cboard.cprogramming.com/c-pro...-behavior.html

Quote:

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Originally Posted by Clairvoyant1332

It is undefined what order the parameters of a function are evaluated in. In practice, many compilers will do them in the reverse order because that's how they get pushed on the stack, but don't depend on that.

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Thanks, makes sense!