Please help!! Syntax error!!

This is a discussion on Please help!! Syntax error!! within the C Programming forums, part of the General Programming Boards category; I keep getting an error in my for statement. Syntax error before "double". Please help anyone!!! #include<stdio.h> #include<stdlib.h> #include<math.h> #include<conio.h> ...

  1. #1
    Registered User
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    Apr 2011
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    Please help!! Syntax error!!

    I keep getting an error in my for statement. Syntax error before "double". Please help anyone!!!

    #include<stdio.h>
    #include<stdlib.h>
    #include<math.h>
    #include<conio.h>

    double factorial(int num); /*function to compute factorial of a no.*/
    int main()
    {
    int terms;
    int i;
    double eCalc=0; /*to store the calculated value of e*/
    double e=2.718281828458;
    double difference;

    do
    {
    printf("Enter no. of terms (n): ");
    scanf("%d",&terms);
    }
    while(terms<=0); /*continue to loop until a positive value is entered*/


    for(i=0; i<=terms ; i++)
    {
    eCalc+=double(1)/factorial(i); /*using formula e = 1/0! + 1/1! + 1/2! + ... + 1/n!*/
    }

    difference = fabs(e - eCalc);

    printf("\nThe approximate value of e : %.12f",e);
    printf("\nCalculated mathematical constant e : %.12f",eCalc);
    printf("\nThe difference is : %.12f",difference);

    /*the .12 after the % signs specifies that there are 12 decimal*/
    /*places*/

    getch();

    }
    double factorial(int num) /*recursive function to compute factorial*/
    {
    if(num==1||num==0) /*the factorial of zero is also 1, it's a mathematical rule!*/
    {
    return 1;
    }
    /*the control won't reach the following line if the above*/
    /*condition becomes true as the 'return' would also exit*/
    /*the function*/
    return num * factorial(num - 1);
    }

  2. #2
    and the hat of wrongness Salem's Avatar
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    Did you read this?
    << !! Posting Code? Read this First !! >>

    I don't think so, otherwise you would have used code tags.
    That's [code]Your code here[/code]

    Try and "Edit" your post (see icon bottom right of your post) and correct this.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
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  3. #3
    Registered User
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    Code:
    #include<stdio.h>
    #include<stdlib.h>
    #include<math.h>
    #include<conio.h>
    
    double factorial(int num); /*function to compute factorial of a no.*/
    int main()
    {
    int terms;
    int i;
    double eCalc=0; /*to store the calculated value of e*/
    double e=2.718281828458;
    double difference;
    
    do
    {
    printf("Enter no. of terms (n): ");
    scanf("%d",&terms);
    }
    while(terms<=0); /*continue to loop until a positive value is entered*/
    
    
    for(i=0; i<=terms ; i++)
    {
    eCalc+=double(1)/factorial(i); /*using formula e = 1/0! + 1/1! + 1/2! + ... + 1/n!*/
    }
    
    difference = fabs(e - eCalc);
    
    printf("\nThe approximate value of e : %.12f",e);
    printf("\nCalculated mathematical constant e : %.12f",eCalc);
    printf("\nThe difference is : %.12f",difference);
    
    /*the .12 after the % signs specifies that there are 12 decimal*/
    /*places*/
    
    getch();
    
    }
    double factorial(int num) /*recursive function to compute factorial*/
    {
    if(num==1||num==0) /*the factorial of zero is also 1, it's a mathematical rule!*/
    {	
    return 1;
    }
    /*the control won't reach the following line if the above*/
    /*condition becomes true as the 'return' would also exit*/
    /*the function*/
    return num * factorial(num - 1);
    }
    Last edited by tanik07; 04-07-2011 at 05:51 AM.

  4. #4
    a_capitalist_story
    Join Date
    Dec 2007
    Posts
    2,652
    How can you program if you can't even read?

    I don't think so, otherwise you would have used code tags.
    That's [ code ]Your code here[ /code ]
    without the spaces.

    Code:
    eCalc+=double(1)/factorial(i); /*using formula e = 1/0! + 1/1! + 1/2! + ... + 1/n!*/
    If you're trying to cast 1 as a double, the proper syntax is

    Code:
    eCalc+=(double)1/factorial(i); /*using formula e = 1/0! + 1/1! + 1/2! + ... + 1/n!*/

  5. #5
    Registered User
    Join Date
    Apr 2011
    Posts
    8
    Thank you!!!

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