Hi,
I am a little confused about certain commands related to pointers & arrays.
Though I understand the what the output would be however, i dont understand the logic behind the output of &arr+1 because when we specfiy an array by its name or with "&" ampersand character we are refering to the first element of the array. But the second statement refers to the whole array as one element.Code:arr[5] = {1,2,3,4,5}; printf ("%u %u), arr+1,&arr+1);
> But the second statement refers to the whole array as one element.
Yes, that is correct.
arr is the equivalent of &arr[0]
But &arr is a completely different thing - it points to the WHOLE array.
As a type, &arr (for a single dimension array) has the same type as a pointer to a 2D array with the same sized minor dimension.
Consider
Code:int a[5]; int b[10][5]; int (*pa)[5]; pa = &a; pa = b; // b[0][0] pa++; // b[1][0]
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
