Thread: Pointer notation help!

my_code[x] is equivalent to *(my_code + x).

Of course, the instructor probably wants something more like:

Code:

int *swap1 = &my_code[0];
int *swap2 = &my_code[2]; // Or: int *swap2 = my_code + 2 (see above)
temp = *swap1;
*swap1 = *swap2;
*swap2 = temp;

Or maybe your instructor wants a function for it, that you'd call like: swap(&my_code[0], &my_code[2]);
...and is declared like: void swap(int *first, int *second)

Originally Posted by nonoob

We'd have to see the code and the parameter declarations. my_code[0] my already be a pointer... or a huge struct. Can't tell.

The OP said the posted code swaps numbers in an array.