finding smallest of 2 dimensional array

[vlad_i]

I need help with my code. I need to find the smallest and largest of each row of a two dimensional array, coming from a structure....
the structure has 3 different skaters and each one has a two dimensional array as follows
(example is just of one skater)

here is the array
0 2 1 1 1 0 1 0 1 1 1 1
1 2 2 2 2 1 2 1 2 2 2 2
2 1 1 1 1 0 0 2 1 2 1 2
2 1 1 1 1 1 2 1 1 1 1 1
2 2 2 2 1 2 3 3 2 3 2 1
1 1 1 2 2 0 0 0 1 2 1 1
1 0 2 2 1 1 1 2 2 2 2 1
1 1 2 2 1 1 1 1 2 2 1 1

the structure is skater[x].scores[][];

{
	
int i = 0;
int smallest[7];
int f;
int j;
int a;

	while ( i < count)
	{
		for ( j = 0; j < 8; j++)
		{
			for ( a = 0; a<12; a++)
			{
				smallest[j] = skater[i].scores[j][a];
				if( smallest[j]< skater[i].scores[j][a+1] );
				smallest[j] = skater[i].scores[j][a+1];
			}
			printf ( "%d\n", smallest[j]);
		}
		
		printf( "\n\n");
		i++;
	}

[quzah]

Use code tags.

[code] ...your code goes in here... [/code]

Here's the logic:

for each row
    for each column
        if here[ row ][ column ] < smallest
            set smallest to this value

You can do the same thing for biggest. The only change you want is to make an array with as many elements as you have rows, and use it to store the lowest or highest for that row.


Quzah.

[vlad_i]

So i tried switching it around but its still not working really. I need the smallest of each row stored into a 1 dimensional array smallest[j]. any other suggestions?

while ( i < count)
	{
		for ( j = 0; j < 8; j++)
		{
			for ( a = 0; a<12; a++)
			{
				if( smallest[j]> skater[i].scores[j][a] );
				smallest[j] = skater[i].scores[j][a];
			}
			printf ( "%d\n", smallest[j]);
		}

[quzah]

So i tried switching it around but its still not working really.

What does "not really working" mean?

f( smallest[j] > skater[i].scores[j][a] );
				smallest[j] = skater[i].scores[j][a];

There are two problems.

Quzah.

[nonoob]

if (smallest[j] > skater[i].scores[j][a])
    smallest[j] = skater[i].scores[j][a];
if (largest[j] < skater[i].scores[j][a])
    largest[j] = skater[i].scores[j][a];

And you need to initialize smallest and largest arrays.