Hello, i have tried to read how I am supposed to pass a vector to a function.
When dealing with a single float number we pass the number by it's variable name. And if we want to change a floating number in a function I pass the adress &floatname, and in the function I change it by saying *floatname=blabla.
But this does not apply to vectors? No matter if I want to change the vector or just use it in a function I give it in to the function by "vectorname[]".?
regards
There's no such thing as a 'vector' in C. Assuming you mean arrays...Also consider reading this.Code:void foo( type name[], size_t num ) { ... } type name[ ARRAYSIZE ]; foo( name, ARRAYSIZE );
Quzah.
Hope is the first step on the road to disappointment.
Perhaps you mean to post in the C++ forum?
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I did not mean to do that no. I am programming in C.Originally Posted by iMalc
And yes I meant arrays not vectors.
But can anyone confirm what I wrote in my first post. I tried to test it with some code, and it seemed to work:
So can confirm that this allways work? That is: We pass the array to a function the same way, no matter if we want to change it contents or just use its contents?Code:#include <stdio.h> #include <stdlib.h> #include <math.h> void fun(float arr[]); int main(){ float ar[10]; fun(ar); int i; for (i=0;i<=10;i++) printf("Element %i=%f\n",i, ar[i]); } void fun(float table[]){ int i; for (i=0;i<=9;i++) table[i]=i+1; }
Yes, you pass them the same regardless if you intend to change its contents or not.
Quzah.
Hope is the first step on the road to disappointment.
Ok, thanks for your reply! it is interesting that arrays is so much more easy to handle than ordinary floats, but I guess the answers lie in the link you provided me with. I should read through all that when I have time.
