read a number with scanf() and read char[] with fgets()

[nutzu2010]

#include <stdio.h>
#include <string.h>



int main()
{
	int n;
	char s[30];
	scanf("%d",&n);
	fgets(s,sizeof(s),stdin);
	printf("n=%d s=%s",n,s);
	getch();
	return 0;
}

s[] skips reading,and s[] has only "\n"
how avoid this?(s I want to also contain spaces,so read s[] with scanf is not a solution)

[Bayint Naung]

fflush vs gets

[Salem]

It's best avoided by not mixing scanf() with fgets().

Read everything into a buffer using fgets().

Then use say sscanf to extract what you need, and validate what was input (not that sscanf is particularly good at validating)

[nutzu2010]

I read almost the entire article posted Bayint Naung and I thought about this:

#include <stdio.h>
#include <string.h>



int main()
{
	int n;
	char s[30],mess[2];
	scanf("%d",&n);
	fgets(mess,sizeof(mess),stdin);
	fgets(s,sizeof(s),stdin);
	printf("n=%d s=%s",n,s);
	getch();
	return 0;
}

read a another char[] only for mess...so mess[] keep the "\n" ,skip read mess[] and jump to read s[] (sorry for my english)
is good code?

[claudiu]

That is fairly pointless, and as Salem suggested the easiest way is to avoid scanf here. Generally scanf is a bad function to use when you are getting input from the user and not from a predefined input file. The user can type in anything(see the Infinite monkey theorem) and particularly something that scanf can't handle properly.

[quzah]

If you insist on mixing them, simply pay attention to your return values:

if( fscanf( place, "%d", &number ) == 1 )
... yay a number
else
if( fgets( buf, bufsize, place ) )
... yay stuff
else
... a fail is you

Quzah.