Program Of Even Or Odd

write a function which ask a user to type a number, it then tells whether the number input is Even Or Odd?

Ok, easy stuff... what have you got so far... Post your code and lets see what we can do...

Use the modulo % operator.

Originally Posted by CommonTater

Ok, easy stuff... what have you got so far... Post your code and lets see what we can do...

Code:

#include<stdio.h>
#include<conio.h>
void even(void);
void main(void)
{
clrscr();
even();

even();
getche();
}

void even(void)
{
int x;
printf("\n\nType A Number :");
scanf("%d",&x);
if(x%2==0)
{printf("\n\nYou Typed Even Number");}
else
{
printf("\n\nYou Typed Odd Number");
}
}

Originally Posted by snayyer

Code:

#include<stdio.h>
#include<conio.h>
void even(void);
void main(void)
{
clrscr();
even();

even();
getche();
}

void even(void)
{
int x;
printf("\n\nType A Number :");
scanf("%d",&x);
if(x%2==0)
{printf("\n\nYou Typed Even Number");}
else
{
printf("\n\nYou Typed Odd Number");
}
}

Hmmm... try it like this....

Code:

#include <stdio.h> 
#include <conio.h>          // warning, not standard C!

int IsOdd(int Num)
  { return Num & 1; }      // odd integers have 1 in bit 0

int main ( void )
 { 
    int uNum = 0;

    clrscr();               // warning, not standard C!

    printf("Enter a number : ");
    scanf("%d", &uNum);
    if ( IsOdd( uNum ) )
     printf(" %d is an odd number", uNum);
   else
    printf(" %d is an even number", uNum);

    return 0;
}

hmmmmmmmmmm