Hi,
Here's the problem, hope someone can help:
I have read in 2 bytes from a file and have to decipher info from these two bytes based on bits!
My inofrmation is stored in the first 7 bits of the 2 bytes and there is other info in the last 9 bits of the 2 bytes. I was told that the >> or << operators can be used? Can anyone show me how I could use them to store say the first 7 bits into a variable called date? Thanks in advance.
Shifting is simple:
Code:#include <stdio.h> #include <stdlib.h> int main ( void ) { unsigned x, date, bit = 21845U; date = bit << 9; for ( x = 0; x < 16U; x++ ) printf ( "%d", !!( date & ( 1 << (unsigned)x ) ) ); return EXIT_SUCCESS; } Output: 0000000001010101-PreludeCode:#include <stdio.h> #include <stdlib.h> int main ( void ) { unsigned x, date, bit = 21845U; date = ( ( bit >> 7 ) << 7 ); for ( x = 0; x < 16U; x++ ) printf ( "%d", !!( date & ( 1 << (unsigned)x ) ) ); return EXIT_SUCCESS; } Output: 0000000010101010
My best code is written with the delete key.
hello Prelude
can you please tell me how does the program work ?
i am intrested how to convert from int to 0&1
thank you,,,
